在web.xml中配置一个启动servlet的方法,
<servlet>
  <servlet-name>springmvc</servlet-name>
  <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
  <init-param>
  <param-name>contextConfigLocation</param-name>
  <param-value>classpath:spring-servlet.xml</param-value>
  </init-param>
  <load-on-startup>1</load-on-startup>
  </servlet>,先加载Springmvc的注解,然后再启动我的方法, <servlet>
    <servlet-name>TimeTaskStart</servlet-name>
    <servlet-class>com.cpsdna.monitor.timetaskstart.TimeTaskStart</servlet-class>
    <load-on-startup>2</load-on-startup>
  </servlet>
  <servlet-mapping>
   <servlet-name>TimeTaskStart</servlet-name>
   <url-pattern>/</url-pattern>
  </servlet-mapping>,load-on-startup为2,TimeTaskStart.java中init方法 public void init() throws ServletException {
  // TODO Auto-generated method stub
  super.init(); 
  service = Executors.newScheduledThreadPool(1);
      
      long initialDelay = 0;
  long period = 60;
  ServiceAndAppMonitor serviceAndAppMonitor = new ServiceAndAppMonitor();
      service.scheduleAtFixedRate(serviceAndAppMonitor, initialDelay, period, TimeUnit.SECONDS);
  },ServiceAndAppMonitor 目前是new,这样new 的话,ServiceAndAppMonitor.java中的@Controller
 public class ServiceAndAppMonitor implements Runnable{
  @Autowired
  private GatewayConfigService gatewayConfigService;
  System.out.println("gatewayConfigService:"+gatewayConfigService);,里面的bean为null,说明没有注入进来,应该是servlet中是对ServiceAndAppMonitor 进行new ,而不是进行注解,那我如何在TimeTaskStart中对ServiceAndAppMonitor不new对象,而进行的注解呢?求助!