怎么实现密码输入错误三次 然后给他提示让他找管理员功能 弹出一个框即可 谢谢大侠
解决方案 »
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if(count!=3){
....... count++;
}else{
JOptionPane.showMessageDialog();
}
public class LoginCount {
private int lCount=0;
public LoginCount() {
}
public int getLCount() {
return lCount;
}
public void LCount() {
lCount++;
}
} <%
String username=request.getParameter("admin_user");
String userpwd=request.getParameter("admin_password");
if(userpwd!=null){
if(userpwd.equals( "success")) {
session.invalidate();
response.sendRedirect( "index.jsp");
}else{
myLCount.LCount();
}
}
int count=myLCount.getLCount();
if(count>2) {
out.println( "登录失败!联系管理员 ");
return;
}
%>
<li style="text-align:left;height:auto;overflow:hidden;"><b>Abnormity detected. The account has been holden systematically and please contact with ICX carrier service team.</b></li>
<li style="text-align:left;"><label class="login_name"> </label>
<input type="button" name="cancel" onclick=location.href="login1.php" id="cancel" value="Back" class="in-submit input"/>
</li>
{else}
<li>
<label class="login_name">Security Question</label>
<input name="security_question" id="security_question" value="{$user_info.question}" class="input in-text" type="text" style="width:150px" readonly="readonly"/></li>
<li>
<label class="login_name">Security Answer</label>
<input name="security_answer" id="security_answer" value="" class="input in-text" type="text" style="width:150px" />
{literal}<script type="text/javascript">
document.getElementById("security_answer").focus();
</script>{/literal}