困扰了2天的jpa问题，求高手解答

  问题如下：
Exception in thread "main" javax.persistence.PersistenceException: Unable to configure EntityManagerFactory
at org.hibernate.ejb.Ejb3Configuration.configure(Ejb3Configuration.java:265)
at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:125)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:52)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:34)
at com.gg.Test.main(Test.java:11)
Caused by: org.xml.sax.SAXParseException: The processing instruction target matching "[xX][mM][lL]" is not allowed.
at com.sun.org.apache.xerces.internal.parsers.DOMParser.parse(DOMParser.java:239)
at com.sun.org.apache.xerces.internal.jaxp.DocumentBuilderImpl.parse(DocumentBuilderImpl.java:283)
at org.hibernate.ejb.packaging.PersistenceXmlLoader.loadURL(PersistenceXmlLoader.java:70)
at org.hibernate.ejb.packaging.PersistenceXmlLoader.deploy(PersistenceXmlLoader.java:89)
at org.hibernate.ejb.Ejb3Configuration.configure(Ejb3Configuration.java:222)
... 4 more persistence.xml文件 <?XML version="1.0"?>  
    <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"  
    xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0">  
       <!-- 实体bean集合 和数据库进行映射 -->  
        <!-- RESOURCE_LOCAL 本地事物 -->  
       <persistence-unit name="aa" transaction-type="RESOURCE_LOCAL">  
          <!-- hibernate 配置 -->  
          <properties>  
             <property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect"/>  
             <property name="hibernate.connection.driver_class" value="org.gjt.mm.mysql.Driver"/>  
             <property name="hibernate.connection.username" value="root"/>  
             <property name="hibernate.connection.password" value="123456"/>  
             <property name="hibernate.connection.url" value="jdbc:mysql://localhost:3306/test"/>  
             <property name="hibernate.hbm2ddl.auto" value="update"/>  
             <property name="hibernate.show_sql" value="false"/>  
             <property name="hibernate.format_sql" value="false"/>  
          </properties>  
       </persistence-unit>  
    </persistence>  实体类：
package com.gg;import javax.persistence.Entity;  
import javax.persistence.GeneratedValue;  
import javax.persistence.GenerationType;  
import javax.persistence.Id;  
  
/** 
 * @Entity标注实体bean 
 *@Id主键 
 *@GeneratedValue增长方式 
 */  
@Entity  
public class Person {  
    @Id @GeneratedValue(strategy=GenerationType.AUTO)  
    private Integer id;  
      
    private String name;  
  
public Integer getId() {  
        return id;  
    }  
    public void setId(Integer id) {  
        this.id = id;  
    }  
    public String getName() {  
        return name;  
    }  
    public void setName(String name) {  
        this.name = name;  
    }  
}  测试类：package com.gg;import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;
import javax.persistence.EntityTransaction;
import javax.persistence.Persistence;
public class Test {
public static void main(String[] args) {
 EntityManagerFactory factory = Persistence.createEntityManagerFactory("aa");  
        EntityManager em = factory.createEntityManager();  
        EntityTransaction et = em.getTransaction();  
        et.begin();  
      //  em.persist(new Person("大连"));  
        et.commit();  
        em.close();  
        factory.close();  
}

}

求解决JPA