为什么不能进入show.jsp???

Question

对constrol.jsp文件修改试试：（仅供参考）
public String getStr(String str)
    {
      try{
        String temp_p=str;
 //       byte[] temp_t=temp_p.getBytes("ISO8859-1");
 //     String temp=new String(temp_t);
 //上面两句改为：String temp=new String(temp_p.getBytes("GB2312"),"ISO8859-1");
        return temp;
       }
       catch(Exception e)
       {
       }
       return "null";
    }

Answer 1

建议你在代码中加入下面代星号的行代码：
<%
user_name=request.getParameter("username");
pass_word=request.getParameter("password");
***System.out.println(user_name);
***System.out.println(pass_word);
  user_name=getStr(user_name);
  pass_word=getStr(pass_word);
***System.out.println(user_name);
***System.out.println(pass_word);sql="select * from login where name='"+user_name+"' and passwd='" + pass_word + "'";
rs=control.executeQuery(sql);
    try
    {
        while(rs.next())
        {
          sql_name=rs.getString("name");
          sql_pass=rs.getString("passwd");
          ***System.out.println(sql_name);
          ***System.out.println(sql_pass);        }
    }

Answer 2

try
    {
        while(rs.next())
        {
          sql_name=rs.getString("name");
          sql_pass=rs.getString("passwd");
        }
    }
改成
try
    {
        while(rs.next()){
        session.setAttribute("user_name",user_name);
        response.sendRedirect("show.jsp");
    }
    else
    {
       session.setAttribute("user_name","");
       response.sendRedirect("err.jsp");
    }
}

Answer 3

if(sql_name.equalsIgnoreCase(user_name) && sql_pass.equals(pass_word))
    {
        session.setAttribute("user_name",user_name);
        response.sendRedirect("show.jsp");
    }
    else
    {
       session.setAttribute("user_name","");
       response.sendRedirect("err.jsp");
    }这个判断就不要了

Answer 4

我没详细的看，不过你的用的bean没有在声明里引入，
应该要import进来，同时要注意路径

Answer 5

而且还没有给属性值
<jsp:setproperty name="同id" property="bean中的属性名" param="jsp内对应的属性名">
(代码手写可能有误，你用工具再写下)

Answer 6

while(rs.next())
        {
          sql_name=rs.getString("name");
          sql_pass=rs.getString("passwd");
        }下面加几个语句
System.out.println("user_name"+user_name);
System.out.println(("pass_word"+pass_word);
System.out.println(("sql_name"+sql_name);
System.out.println(("sql_pass"+sql_pass);看看控制台喷出的是什么?是不是相等,然后再说吧

Answer 7

大侠 alaal(穷街) :
  您好!我按你的指点我加了System.out.println(,,,,)进行测试:
<%
user_name=request.getParameter("username");
pass_word=request.getParameter("password");System.out.println("user_name"+user_name);
System.out.println(("pass_word"+pass_word);//(此处能正确输出user_name和pass_word);  user_name=getStr(user_name);
  pass_word=getStr(pass_word);sql="select * from login where name='"+user_name+"' and passwd='" + pass_word + "'";System.out.println("user_name"+user_name);
System.out.println(("pass_word"+pass_word);//(此处能正确输出user_name和pass_word);rs=control.executeQuery(sql);
    try
    {
        while(rs.next())
        {
          sql_name=rs.getString("name");
          sql_pass=rs.getString("passwd");         System.out.println(("sql_name"+sql_name);
         System.out.println(("sql_pass"+sql_pass);//(此处能正确输出sql_name和sql_pass)
        }
    }
    catch(Exception e)    {
    e.printStackTrace();
    }
    if(sql_name.equalsIgnoreCase(user_name) && sql_pass.equals(pass_word))
    {
        session.setAttribute("user_name",user_name);
        response.sendRedirect("show.jsp");
     System.out.println("user_name"+user_name);
    System.out.println(("pass_word"+pass_word);
    System.out.println(("sql_name"+sql_name);
    System.out.println(("sql_pass"+sql_pass);//这个地方什么结果都不能输出,是那个地方错了呢?麻烦您再帮我看看好吗??谢谢!!
    }
    else
    {
       session.setAttribute("user_name","");
       response.sendRedirect("err.jsp");
    }rs.close();
%>
</body>
</html>