Struts2的配置问题

刚学习这个，在网上找了哈Struts2的配制方法，跟到做，配置好了访问就显示404错误...郁闷啊！哪位大大帮哈小弟~~~~
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web.xml的配置：<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_ID" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>ssh2</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>

<filter>
<filter-name>struts2</filter-name>
<filter-class>
               org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter
                </filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>

</web-app>
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struts.xml的配置（按网上说的放到src的根目录下）：<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.3//EN"
"http://struts.apache.org/dtds/struts-2.3.dtd"><struts>
    <package name="default" namespace="/" extends="struts-default">        <action name="index" class="com.struts2.action.Test1Action" method="execute">
            <result name="success">/test1.jsp</result>
        </action>
    </package>
</struts>
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我的Test1Action：
public class Test1Action extends ActionSupport{
public String execute() throws Exception{

System.out.println("----1----");

return SUCCESS;
}
}
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后台打印的“--------1—---------”都没打印，意思是连这个都没进....
访问地址用什么都不行.....
Help!!!~~~