Struts2配置报错

description The server encountered an internal error () that prevented it from fulfilling this request.exception java.lang.NullPointerException
org.apache.struts2.impl.StrutsActionProxy.getErrorMessage(StrutsActionProxy.java:69)
com.opensymphony.xwork2.DefaultActionProxy.prepare(DefaultActionProxy.java:185)
org.apache.struts2.impl.StrutsActionProxy.prepare(StrutsActionProxy.java:63)
org.apache.struts2.impl.StrutsActionProxyFactory.createActionProxy(StrutsActionProxyFactory.java:39)
com.opensymphony.xwork2.DefaultActionProxyFactory.createActionProxy(DefaultActionProxyFactory.java:58)
org.apache.struts2.dispatcher.Dispatcher.serviceAction(Dispatcher.java:500)
org.apache.struts2.dispatcher.FilterDispatcher.doFilter(FilterDispatcher.java:434)

解决方案 »

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两个基本配置：struts.xml
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.3//EN" "http://struts.apache.org/dtds/struts-2.3.dtd">  <struts>

<package name="myStruts" extends="struts-default" >
<action name="Login" class="com.j1.action.LoginAction">
<result name = "error">pages/error.jsp</result>
<result name = "success">pages/welcome.jsp</result>
</action>

</package>
</struts>
web.xml\
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">  <filter>
   <filter-name>struts2</filter-name>
   <filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
  </filter>
  <filter-mapping>
   <filter-name>struts2</filter-name>
   <url-pattern>/*</url-pattern>
  </filter-mapping>

  <welcome-file-list>
    <welcome-file>pages/Login.jsp</welcome-file>
  </welcome-file-list>
</web-app>感觉都没错，怎么就报上面的错误呢
<result name = "error">pages/error.jsp</result>
  <result name = "success">pages/welcome.jsp</result>
改为
<result name = "error">/pages/error.jsp</result>
  <result name = "success">/pages/welcome.jsp</result>
路径前再加一个斜杠看看！
没用，我刚去再试了一下，都不行。我只是做一个简单的例子，页面如下：<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%@ taglib prefix="s" uri="/struts-tags"%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>

    <title>登陆页面</title>

<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
  </head>

  <body>
  <s:form action = "Login">
   <s:textfield label="用户名" name="username" />
   <s:textfield label="密码" name="password"></s:textfield>
   <s:submit value="登陆" />
  </s:form>
  </body>
</html>
action 如下：
package com.j1.action;public class LoginAction {

private String username ;
private String password;

public String getUsername(){
return username;
}
public void setUsername(String username){
this.username = username;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}

public String execute()throws Exception{

if("gyj".equals(getUsername())&&"123".equals(getPassword())){
return "success";
}else{
return "error";
}
//return "success";
}
}
、========================\
真想不明白为什么？
web.xml中配置filter时，没有指定actionPackages.............
之前你定义过
<package name="myStruts" extends="struts-default" >
  <action name="Login" class="com.j1.action.LoginAction">
  <result name = "error">pages/error.jsp</result>
  <result name = "success">pages/welcome.jsp</result>
  </action>

  </package>
这个包
要怎么指定？？我之前是写默认的：
<package name="default" extends="struts-default">这么写依然不行啊。。
好抓狂！！
如果这是你的第一个struts2程序，请检查你所导入的lib目录中的jar文件是否正确。该程序本身没有问题，已验证。。另外一个无关紧要的提醒：如果请求页面和welcome.jsp、result.jsp不在同一个目录下，3楼的提醒就非常有必要了。。
感谢各位了终于找到原因了。
我把struts.xml放在web-inf/下了。。
现在我把它移到src目录下就可以了。。