新手请教一下 jsp页跳servlet 一直是404未找到

Question

<form action="/loginServlet" method="post"><DIV id=div1>
  <TABLE id=login height="100%" cellSpacing=0 cellPadding=0 width=800 
align=center>
    <TBODY>
      <TR id=main>      
        <TD>    
          <TABLE height="100%" cellSpacing=0 cellPadding=0 width="100%">
            <TBODY>
              <TR>
                <TD colSpan=4>&nbsp;</TD>
              </TR>
              <TR height=30>
                <TD width=380>&nbsp;</TD>
                <TD>&nbsp;</TD>
                <TD>&nbsp;</TD>
                <TD>&nbsp;</TD>
              </TR>
             
              <TR height=40>
                <TD rowSpan=4>&nbsp;</TD>
               
                <TD>用户名：</TD>
                <TD>
                  <INPUT class=textbox id=txtUserName name=txtUserName>
                </TD>
                <TD width=120>&nbsp;</TD>
              </TR>
              <TR height=40>
                <TD>密　码：</TD>
                <TD>
                  <INPUT class=textbox id=txtUserPassword type=password 
            name=txtUserPassword>
                </TD>
              
                <TD width=120>&nbsp;</TD>
              </TR>
              <TR height=40>
                <TD>验证码：</TD>
                <TD vAlign=center colSpan=2>
                  <INPUT id=txtSN size=4 name=txtSN>
                  &nbsp; <IMG src="登录.files/default.gif" border=0> <A id=LinkButton1 
            href="#">不清楚，再来一张</A></TD>
              </TR>
              <TR height=40>
                <TD></TD>
                <TD align=right>
                  <INPUT id=btnLogin type=submit value=" 登 录 " name=btnLogin> <!--onClick="window.open('backstage.html')"> -->
                </TD>
                <TD width=120>&nbsp;</TD>
              </TR>
              <TR height=110>
                <TD colSpan=4>&nbsp;</TD>
              </TR>
            </TBODY>          </TABLE>
        </TD>
      </TR>
      <TR id=root height=104>
        <TD>&nbsp;</TD>
      </TR>
    </TBODY>
  </TABLE>
</DIV><DIV id=div2 style="DISPLAY: none"></DIV></form> <servlet>
   <servlet-name>login</servlet-name>
   <servlet-class>servlet.LoginServlet</servlet-class>
</servlet>

<servlet-mapping>
    <servlet-name>login</servlet-name>
    <url-pattern>/loginServlet</url-pattern>
</servlet-mapping>
跳转出现404错误。type Status reportmessage /LoginServletdescription The requested resource (/LoginServlet) is not available.
浏览器里 http://localhost:8080/LoginServlet
跳转之后，没有项目名，只有servlet名称。xml和表单action路径，我是改了又改。还是404.名字都一样了。不知道哪问题

Answer 1

问题已经解决。
action="LoginServlet"
这样就好了。

Answer 2

你这个解决，可能早晚害死自己。建议用绝对路径，借助于ContextPath，类似于：
<form action="<%=request.getContextPath()%>/loginServlet" method="post">

Answer 3

看返回的代码404代表什么，弄清是客户端或服务端的问题，然后在对应的层做修改。有时候看HTTP的状态码帮助挺大的。