struts2访问不到action问题

<form name="form1" action="loginAction.action" method="post">不建议写相对路径的。如果对路径理解不清晰的话，经常出错。

action="loginAction.action"，action加上你的项目访问路径，如：你项目的访问路径是test，那就改成:/test/loginAction.action，看看你server.xml里面配置的context下的path

按楼上的建议写成这种形式不行:
<form name="form1" action="${pageContext.request.contextPath}/loginAction.action" method="post">写成这样也不行:
<form name="form1" action="/TSP/loginAction.action" method="post">从报错来看,我怀疑是struts.xml的问题,是不是我的action在struts.xml中没有配置对,所以找不到了!

你Action里面的方法是用的execute()

配置没问题，这个错误提示说明loginAction.action 不是被当做一个Action处理的，而是当做路径处理的，和.jsp一样，个人觉得是在过滤器里面出现问题了
个人意见

Web.xml配置了StrutsServet？？？
没有这个Servlet怎么转发你的请求？

楼上说loginAction.action 不是被当做一个Action处理的，而是当做路径处理的
麻烦给看看过滤器是那个地方处理的有问题!
loginFilter的代码如下:
import java.io.IOException;
import javax.servlet.Filter;
import javax.servlet.FilterChain;
import javax.servlet.FilterConfig;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;import org.apache.commons.lang.StringUtils;
import org.apache.commons.logging.Log;
import org.apache.commons.logging.LogFactory;import com.bonsoft.oa.util.Constants;
import com.bonsoft.oa.util.session.*;public class LoginFilter implements Filter {
private FilterConfig config;
protected final Log logger = LogFactory.getLog(getClass());
private String excluded;
private static final String EXCLUDE = "exclude";
private boolean no_init = true; // private LoginServlet loginServlet;
public void setFilterConfig(FilterConfig paramFilterConfig) {
if (this.no_init) {
this.no_init = false;
this.config = paramFilterConfig;
if ((this.excluded = paramFilterConfig.getInitParameter("exclude")) != null)
this.excluded += ",";
}
} private String getActionName(String actionPath) {
logger.info("filter actionPath===="+actionPath);
StringBuffer actionName = new StringBuffer();
try {
int begin = actionPath.lastIndexOf("/");
if (begin >= 0) {
actionName.append(actionPath.substring(begin, actionPath.length()));
}
} catch (Exception e) {
}
return actionName.toString();
} private boolean excluded(String paramString) {
logger.info("paramString====" + paramString);
logger.info("excluded====" + this.excluded);
logger.info(this.excluded.indexOf(paramString + ",")+"*********");
if ((paramString == null) || (this.excluded == null))
return false;
return (this.excluded.indexOf(paramString + ",") >= 0);
} public void destroy() {
// TODO Auto-generated method stub } public void doFilter(ServletRequest request, ServletResponse response, FilterChain arg2) throws IOException,
ServletException {
logger.info(request.getProtocol()); HttpServletRequest req = (HttpServletRequest) request;
HttpServletResponse resp = (HttpServletResponse) response;
String url = req.getRequestURI();
String actionName = getActionName(url);
logger.info("actionname===="+actionName);
String login = req.getContextPath() + "/jsp/zh_CN/login/login.jsp";
if (!excluded(actionName)) {
logger.info("not the exclude name..................");
UserSessionInfo userSessionInfo = (UserSessionInfo) req.getSession().getAttribute(Constants.USER_SESSION);
if (userSessionInfo == null) {
logger.info("session null.............");
resp.sendRedirect(login);
return;
}
}
try {
arg2.doFilter(request, response);
} catch (Exception e) {
logger.error("LoginFilter Fail:" + e.getMessage(), e);
}
} public void init(FilterConfig arg0) throws ServletException {
// TODO Auto-generated method stub
this.config = arg0;
if ((this.excluded = arg0.getInitParameter("exclude")) != null)
this.excluded += ",";
this.no_init = false;
}
}

其实要看是不是拦截器出了错误，只要把struts的拦截器卸载web.xml文件的最上面就行了，web.xml的读取顺序是从上到下的。如果能成功运行，就说明是LoginFilter这个拦截器出问题啦

补充一下，web.xml读取从上到下是针对同种类型的标签的，比如<filter-mapping>

在web.xml中把loginFilter已经注释掉,现在可以直接访问到loginAction了,还是报错!HTTP Status 404 - /oa/loginAction.action--------------------------------------------------------------------------------type Status reportmessage /oa/loginAction.actiondescription The requested resource is not available.
--------------------------------------------------------------------------------Apache Tomcat/7.0.47不能确认问题出在什么地方了!
是struts.xml配置的问题,还是action路径的问题?
求高手解答!谢谢了!
struts.xml配置如下:<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.3//EN"
"http://struts.apache.org/dtds/struts-2.3.dtd">

<struts>
<include file="struts-default.xml" />
    <package name="web"  extends="struts-default">
    <global-results>
     <result name="error">/jsp/zh_CN/error/syserror.jsp
</result>
  </global-results>
  <global-exception-mappings>
<exception-mapping result="error" exception="java.lang.Exception" />
  </global-exception-mappings>

  <action name="loginAction" class="com.oa.login.action.LoginAction">
<result name="success">/index.jsp</result>
  </action>

    </package>
</struts>

貌似没有在你的web.xml中没有看到你的servlet配置，你如何转发...

我用的spring的全注解和struts2,这个应该不需要在web.xml中配置servlet吧!

调试易

struts2访问不到action问题

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