js处理JSON数据去重（大婶快来）

Question

json javajsjson

Answer 1

var $a ={                                                      
    "total":3,                                                      
    "rows":[                                                          
        {"code":"001","name":"北京市","qymc":"雪花啤酒","pfkmc":"雪花排气口1#"},         
        {"code":"002","name":"北京市","qymc":"雪花啤酒","pfkmc":"雪花排气口2#"},         
        {"code":"003","name":"上海市","qymc":"雪花啤酒","pfkmc":"雪花排气口2#"}
    ]                                                          
}

$b = {"total":0,"rows":[]};
var tem = $a.rows;
var len = tem.length;
var i=0;
var arr = [];
for(; i<len; i++){
var t = tem[i];
if(arr.indexOf(t['name']) ==-1){
arr.push(t['name']);
$b.rows.push(t);
$b.total++;
}

}

var newarr = $b;