data:{
username:$('#username input[name=username]').val(),
password:$('#password input[name=password]').val()
}选择器错了。。对象都没有获取到data:{
username:$('input[name=username]').val(),
password:$('input[name=password]').val()
}
username:$('#username input[name=username]').val(),
password:$('#password input[name=password]').val()
}选择器错了。。对象都没有获取到data:{
username:$('input[name=username]').val(),
password:$('input[name=password]').val()
}
两点错误,第一个地方版主已经说了jquery的选择器出错,第二个是最致命的ajax后台无需跳转,直接用response输出即可protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
String u = request.getParameter("username");
String p = request.getParameter("password");
response.setContentType("text/plain;charset='utf-8'");
PrintWriter pw=response.getWriter();
if(u.equals("admin")&&p.equals("123")){
pw.write("登陆成功!");
}else{
pw.write("用户名或密码错误!");
}
"username":$('input[name=username]').val(),
"password":$('input[name=password]').val()
}