给你一段有用的代码:Calendar xmas = new GregorianCalendar(1998, Calendar.DECEMBER, 25);
Calendar newyears = new GregorianCalendar(1999, Calendar.JANUARY, 1);
// Determine which is earlier
boolean b = xmas.after(newyears); // false
b = xmas.before(newyears); // true
// Get difference in milliseconds
long diffMillis = newyears.getTimeInMillis()-xmas.getTimeInMillis();
// Get difference in seconds
long diffSecs = diffMillis/(1000); // 604800
// Get difference in minutes
long diffMins = diffMillis/(60*1000); // 10080
// Get difference in hours
long diffHours = diffMillis/(60*60*1000); // 168
// Get difference in days
long diffDays = diffMillis/(24*60*60*1000); //
Calendar newyears = new GregorianCalendar(1999, Calendar.JANUARY, 1);
// Determine which is earlier
boolean b = xmas.after(newyears); // false
b = xmas.before(newyears); // true
// Get difference in milliseconds
long diffMillis = newyears.getTimeInMillis()-xmas.getTimeInMillis();
// Get difference in seconds
long diffSecs = diffMillis/(1000); // 604800
// Get difference in minutes
long diffMins = diffMillis/(60*1000); // 10080
// Get difference in hours
long diffHours = diffMillis/(60*60*1000); // 168
// Get difference in days
long diffDays = diffMillis/(24*60*60*1000); //
解决方案 »
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{
int days=-1;
if((dt_end.getTime()-dt_beg.getTime())>=0)
{
days=new Long((dt_end.getTime()-dt_beg.
getTime())/(24*3600*1000l)).intValue()+1;
}
return days;
}
以上是返回两个日期相差的天数,小时,分钟,秒你自己去实现吧