如何在applet中实现网页的过渡

Question

apple.tgetAppletContext().showDocument();

Answer 1

private void ShowHTMLPage(String s, String s1)
    {
        AppletContext appletcontext = applet.getAppletContext();
        URL url = null;
        try
        {
            url = new URL(s);
        }
        catch(MalformedURLException malformedurlexception)
        {
            DisplayMsg(malformedurlexception.getMessage());
        }
        appletcontext.showDocument(url, s1);
    }

Answer 2

import java.applet.AppletContext;
import java.net.MalformedURLException;
import java.net.URL;
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