jspsmart的下载问题

Question

mySmartUpload.downloadFile("../loadfiles/upload/h.class");
要绝对路径的吧~

Answer 1

String path=null;
String type=request.getParameter("type");
String filename=request.getParameter("filename");
String downloadname=request.getParameter("downloadname")+filename.substring(filename.lastIndexOf("."));
if(type.equals("a")){
path=BeansConstants.aPath;
}else if(type.equals("b")){
path=BeansConstants.bPath;
}
if(path!=null){
mySmartUpload.initialize(pageContext);
mySmartUpload.downloadFile(path+filename,"APPLICATION/OCTET-STREAM",downloadname);
}
%>

Answer 2

<%
//处理附件
String accessories=request.getParameter("accessories");
byte[] tmpbyte=accessories.getBytes("ISO8859-1") ;
accessories= new String(tmpbyte); String fileName = accessories.substring( accessories.lastIndexOf("/") + 1, accessories.length()).toString();
//读到流中
InputStream inStream=new FileInputStream("C:/Program Files/Apache Group/Tomcat 5.0/webapps/ROOT/" + accessories );;
//设置输出的格式
response.reset();
response.setContentType("bin;text/html; charset=gb2312");// response.setContentType("APPLICATION/OCTET-STREAM");
  response.setHeader("Connection",  "close");
response.setHeader("Content-Type",  "application/octet-stream");// response.setHeader("Content-Disposition",  "attachment;filename="+ Utilities.URLEncode(fileName));
response.addHeader("Content-Disposition","attachment; filename=\"" + fileName + "\""); //循环取出流中的数据
byte[] b = new byte[100];
int len;
while((len=inStream.read(b)) >0)
response.getOutputStream().write(b,0,len);
inStream.close();%>这是我写的

Answer 3

<meta http-equiv="Content-Type" content="application/msword;charset=gb2312">
改为
response.setContentType("application/msword;charset=gb2312");

Answer 4

不知大家有没有jspsmartupload，从oracle数据库中进行文件下载的例子，能给我发一份[email protected]