servlet

Question

你的tomcat 的版本，5点零以后以需要在web.xml中配置映射

Answer 1

http://localhost:8080/servlet/servlet文件名
就可以了

Answer 2

怎么配置映射呀？
楼上：http://127.0.0.1:8080/servletAPI/servlet/BasicServlet 这个地址也不成功

Answer 3

/web-inf/web.xml 中添加如下：
<servlet>
<servlet-name>yourServletName</servlet-name>
<servlet-class>yourServletClassPath</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>yourServletName</servlet-name>
<url-pattern>/demo</url-pattern>
</servlet-mapping>

Answer 4

写成这样可以吗？
<servlet>
<servlet-name>BasicServlet</servlet-name>
<servlet-class>d:/jakarta-tomcat-4.1.27/webapps/servletAPI/classes/basicServlets/BasicServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>BasicServlet</servlet-name>
<url-pattern>/demo</url-pattern>
</servlet-mapping>

Answer 5

把你的servlet类 放到 web-inf/class 下
<servlet-class>d:/jakarta-tomcat-4.1.27/webapps/servletAPI/classes/basicServlets/BasicServlet</servlet-class>
</servlet>
这里改为:
<servlet-class>basicServlets/BasicServlet</servlet-class>
</servlet>