帮我看看，怎么编译不通过

Question

struts.jar要加到程序的classpath里面去,自己写的类也要加到里面去才能访问

Answer 1

检查一下是否有servlet.jar？

Answer 2

编译的时候使用
javac -cp %CLASSPATH%;servlet.jar com/example/ValidateEmployeeAction.java

Answer 3

servlet.jar已经加了啊，不然EmployeeForm怎么能编译通过呢？
package com.example;
import org.apache.struts.action.ActionForm;
public class EmployeeForm extends ActionForm
{
private String name="";
private String department="";
private String [] skills;
public String getName(){
return name;
}
public void setName(String name){
this.name=name;
}
public String getDepartment(){
return department;
}
public void setDepartment(String department){
this.department=department;
}
public String [] getSkills(){
return skills;
}
public void setSkills(String [] skills){
this.skills=skills;
}
}
这个编译没问题，是不是意味着struts安装没问题呢？

Answer 4

哦，弄好了，但还是说EmployeeForm找不到，我把它们放在同一目录下，是不是要写一些什么include语句阿，我对java不熟悉，

Answer 5

javax.srevlet.http.HttpServletResponse
在servlet.jar里面

Answer 6

那个问题我已经解决了，是servlet打成了srevlet了，现在就是我自己编写的一个EmployeeForm类想在ValidateEmployeeAction里调用该类的方法，应该怎样做？

Answer 7

struts-config.xml
.................
  <form-beans>
    <form-bean name="employeeForm"
           type="com.example.EmployeeForm"/>
  </form-beans>
.................
文件 /WEB-INF/classes/com/example/EmployeeForm.class

Answer 8

................
<action   path="/validateEmployee"
          type="com.example.ValidateEmployeeAction"
          name="employeeForm"
          scope="request">
      <forward name="success" path="/yourgoal.jsp"/>
</action>
................
注意action的name应该与form-bean的name相同

Answer 9

你看看这是我的struts-config.xml,我直接放在webapps自建工程struts下面
<?xml version="1.0" encoding="ISO-8859-1" ?>
<!DOCTYPE struts-config PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 1.0//En"
"http://jakarta.apache.org/struts/dtds/struts-config_1_0.dtd">
<struts-config>
<form-beans>
<form-bean name="EmployeeForm" type="com.example.EmployeeForm"/>
</form-beans>  <action-mappings>
<action path="/validateEmployee"
type="com.example.ValidateEmployeeAction"
name="EmployeeForm"
scope="request"
input="/inputContent.jsp">
<forward name="success" path="/OutputContent.jsp"/>
</action>
</action-mappings>
</struts-config>这是struts下的web.xml
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app PUBLIC
  "-//Sun Microsystems, Inc.//DTD Web Application 2.2//EN"
  "http://java.sun.com/j2ee/dtds/web-app_2_2.dtd">
<web-app>
<servlet>
<servlet-name>action</servlet-name>
<servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
<init-param>
<param-name>application</param-name>
<param-value>ApplicationResources</param-value>
<init-param>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>action</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<taglib>
<taglib-uri>/bean</taglib-uri>
<taglib-location>/WEB-INF/struts-bean.tld</taglib-location>
</taglib>
<taglib>
<taglib-uri>/html</taglib-uri>
<taglib-location>/WEB-INF/struts-html.tld</taglib-location>
</taglib>
<taglib>
<taglib-uri>/logic</taglib-uri>
<taglib-location>/WEB-INF/struts-logic.tld</taglib-location>
</taglib>
<taglib>
<taglib-uri>/template</taglib-uri>
<taglib-location>/WEB-INF/struts-template.tld</taglib-location>
</taglib>
</web-app>所有的tld我放在了WEB-INF下面，也在它下面建立lib文件夹，拷贝struts.jar,它好像不读我的web.xml