太好了,谢谢大家! 只要小数点两位的话 diewikwang(coconut) ,lgs6715(),sasa_sasa(乡巴佬) 的最简单 huanxiangzhe24(huanxiangzhe24) 的是比较好 cui_yihao(pg) 这个人比较有钻的精神, <%@page import="java.math.*"%> <% double aa=15.3265; double bb; double cc;bb=aa*100; cc=(int)Math.round(bb)/100.00; out.println ("the result is :" + cc+"<br>"); //15.33 double a=82.6984; BigDecimal b=new BigDecimal(a); BigDecimal c=b.setScale(3,BigDecimal.ROUND_HALF_UP);//82.698 BigDecimal d=b.setScale(2,BigDecimal.ROUND_HALF_UP); //82.70 BigDecimal e=b.setScale(1,BigDecimal.ROUND_HALF_UP); //82.7 BigDecimal f=b.setScale(0,BigDecimal.ROUND_HALF_UP); //83 out.println ("the result is :"+c+"<br>"); out.println ("the result is :"+d+"<br>"); out.println ("the result is :"+e+"<br>"); out.println ("the result is :"+f+"<br>"); %>好了,大家给了我这么多的方法,给了我这么多的鼓励,我加分来谢谢大家 来者有份!同时为了让更多需要这种帮助的人能得到大家的帮助,所以暂不结贴, 但这贴以后的发贴的同志,将不会有分了,不便之处,敬请谅解!
dotI = temp1.indexOf(".");
tempLen = temp1.length();
if (dotI+3<=tempLen){tempLen =dotI+3;}
temp1=temp1.substring(0,tempLen);不知有没有好的方法
double bb;bb=(aa*100)/100.0;
System.out.println(String.valueOf(bb));But the result is 15.3265 still
double bb;bb=(aa*100)/100.0;
System.out.println(String.valueOf(bb));But the result is 15.3265 still
double aa = 123.23232323;
int bb = (int)(aa * 100);
System.out.println(bb/100.00);
BigDecimal b=new BigDecimal(a);
BigDecimal c=b.setScale(2,BigDecimal.ROUND_HALF_UP))//四舍五入保留二位;
a=c.floatValue();除了四舍五入外,还有截断,五舍六入等保留方法。
不过要import java.math.*
aa = Math.round(aa*100)/100.00
double bb;
double cc;bb=aa*100;
cc= (int)Math.round(bb)/100.0 ;
out.println ("the result is :" + cc+"<br>"); //15.33
double y;
y = (int)Math.round(x * 100)/100.00;
out.println("the result is :"+ y);
* 四舍五入
* @param f double 类型,要进行四舍五入的数字
* @param position 要保留小数位的个数
* @return String
* @throws Exception
*/
public String round (double f,int position) throws Exception {
String sf = String.valueOf(f);
int i = sf.indexOf(".");
String s1 = "" ,s2 = "";
if(sf.substring(i+1).length() <= position){
return String.valueOf(f);
}
if(position == 0){
s1 = sf.substring(i-1,i);
s2 = sf.substring(i+position+1,i+position+2);
if(Integer.parseInt(s2) >=5 ){
s1 = String.valueOf(Integer.parseInt(s1)+1);
}
return sf.substring(0,i-1)+s1;
}else{
s1 = sf.substring(i+position, i+position+1);
s2 = sf.substring(i+position+1,i+position+2); if(Integer.parseInt(s2) >=5 ){
s1 = String.valueOf(Integer.parseInt(s1)+1);
}
return sf.substring(0,i+position)+s1;
} }
只要小数点两位的话 diewikwang(coconut) ,lgs6715(),sasa_sasa(乡巴佬) 的最简单
huanxiangzhe24(huanxiangzhe24) 的是比较好
cui_yihao(pg) 这个人比较有钻的精神,
<%@page import="java.math.*"%>
<%
double aa=15.3265;
double bb;
double cc;bb=aa*100;
cc=(int)Math.round(bb)/100.00;
out.println ("the result is :" + cc+"<br>"); //15.33
double a=82.6984;
BigDecimal b=new BigDecimal(a);
BigDecimal c=b.setScale(3,BigDecimal.ROUND_HALF_UP);//82.698
BigDecimal d=b.setScale(2,BigDecimal.ROUND_HALF_UP); //82.70
BigDecimal e=b.setScale(1,BigDecimal.ROUND_HALF_UP); //82.7
BigDecimal f=b.setScale(0,BigDecimal.ROUND_HALF_UP); //83
out.println ("the result is :"+c+"<br>");
out.println ("the result is :"+d+"<br>");
out.println ("the result is :"+e+"<br>");
out.println ("the result is :"+f+"<br>");
%>好了,大家给了我这么多的方法,给了我这么多的鼓励,我加分来谢谢大家
来者有份!同时为了让更多需要这种帮助的人能得到大家的帮助,所以暂不结贴,
但这贴以后的发贴的同志,将不会有分了,不便之处,敬请谅解!