servlet中zip文件下载问题

Question

看这里，试一下这个:ServletOutputStream out = response.getOutputStream();request.setCharacterEncoding("GB2312");String file="d:\\down\\"+request.getParameter("filename");int BUFFER = 2048;byte data[] = new byte[BUFFER];BufferedInputStream origin = null;FileInputStream fis = new FileInputStream(fileName);int numRead=0;int size=0;origin = new BufferedInputStream(fis, BUFFER);response.setContentType( "application/OCTET-STREAM" );response.setHeader("Content-Disposition","attachment; filename="+request.getParameter("filename")+";");while (numRead != -1) {      numRead= origin.read(data, 0, BUFFER);
      out.write(data, 0, numRead);
      size+=numRead;
    }origin.close();

Answer 1

原代码如下：
res.setHeader("Content-Disposition","attachment;filename=zipfile.zip");
 res.setHeader("Connection","close");  
res.setContentType("application/octet-stream");
ServletOutputStream out=response.getOutputStream();;
out = res.getOutputStream();
// 创建ZIP文件输出流
System.out.println("create zip stream");
ZipOutputStream zip = new ZipOutputStream(out);
String oln;  byte [] byt;
while(rs.next())
{
String val = rs.getString("uid");
fname = val.substring(val.length() - 8)+".R12");
zip.putNextEntry(new ZipEntry(fname));
oln = "kjasdfijsdifjsdfj \r\n" ;
byt = oln.getBytes();
zip.write(byt, 0, byt.length);
zip.closeEntry();
}

zip.finish(); 
zip.close();

Answer 2

zip文件，直接给个联接就可以下载了呀！何必那么麻烦呢？
打开问题的话，就把method=get