Tomcat下进入相应目录时，总是列出所有的文件列表，我如何关闭此功能？

Question

呵呵，在
%TOMCAT_HOME%/conf/web.xml
中，将
    <servlet>
        <servlet-name>default</servlet-name>
        <servlet-class>
          org.apache.catalina.servlets.DefaultServlet
        </servlet-class>
        <init-param>
            <param-name>debug</param-name>
            <param-value>0</param-value>
        </init-param>
        <init-param>
            <param-name>listings</param-name>
            <param-value>true</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>改为
    <servlet>
        <servlet-name>default</servlet-name>
        <servlet-class>
          org.apache.catalina.servlets.DefaultServlet
        </servlet-class>
        <init-param>
            <param-name>debug</param-name>
            <param-value>0</param-value>
        </init-param>
        <init-param>
            <param-name>listings</param-name>
            <param-value>false</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

Answer 1

TOMCAT中，由
        <init-param>
            <param-name>listings</param-name>
            <param-value>false</param-value>
        </init-param>来控制是否列目录列表！
true表示列 false表示不列

Answer 2

GOOD~~LUCK！！
有问题MAIL我：[email protected]

Answer 3

<init-param>
            <param-name>listings</param-name>
            <param-value>false</param-value>
        </init-param>

Answer 4

  改了之后不在显示列表，但报错：The requested resource (/timesheet/) is not available.我想使之返回自己定义的错误页面该怎么做？

Answer 5

在web.xml的</web-app>之前，加入以下XML代码：<error-page>
<error-code>404</error-code>
<location>/notFileFound.jsp</location>
</error-page>就OK了~~所以，建议你先学学XML语言~~
:)

Answer 6

notFileFound.jsp就是要做处理的JSP页面！
他前面的‘/’表示WEB根！