JSP中如何通过判断条件后连接到新页面？？？

Question

<%
String  path  =  "loginerror.jsp";
pwd=request.getParameter("password");
if(pwd.compareTo(enterprisereomte.getUserPwd())==0){
       path = "success.jsp";
}
else
{
      session.invalidate();
       path = "loginerror.jsp";
}
response.sendRedirect(path);
%>

Answer 1

用javascript也行啊
<script language="JavaScript">
  window.location.replace("a.jsp");
</script>

Answer 2

response.sendRedirect(response.encodeURL(_redirectURL));

Answer 3

<%
String pwd；
pwd=request.getParameter("password");
int compare=pwd.compareTo(enterprisereomte.getUserPwd());
if(compare==0)//密码一致
{
%>
<script>
location.href="***.jsp";
</script>    
<%
}
else //密码错误
{
<%
<script>
location.href="error.jsp";
</script>
%>
}

Answer 4

写错  上面是
<%
String pwd；
pwd=request.getParameter("password");
int compare=pwd.compareTo(enterprisereomte.getUserPwd());
if(compare==0)//密码一致
{
%>
<script>
location.href="***.jsp";
</script>    
<%
}
else //密码错误
{
%>
<script>
location.href="error.jsp";
</script>
<%
}
%>

Answer 5

String pwd；
pwd=request.getParameter("password");
int compare=pwd.compareTo(enterprisereomte.getUserPwd());
if(compare==0)//密码一致   <jsp:forward page="***.jsp"/>     else //密码错误   <jsp:forward page="error.jsp"/>