JSP中如何获得xmlhttp所send的变量

Question

/**
*<P>功能：初始化处理
*<P>E.g Open(request);//此request中须由javascript XMLHTTP请求
*/
    public String Open(HttpServletRequest request) throws Exception
    {
        try
        {
            BufferedReader Stream = request.getReader();
            String sline = " ";
            String S = "";
            do
            {
                if(sline == null)
                    break;
                sline = Stream.readLine();
                if(sline != null)
                    S = String.valueOf(S) + String.valueOf(sline);
            } while(true);
            String xml = new String(S.getBytes("ISO-8859-1"), "GB2312");
            return xml;
        }
        catch(Exception e)
        {
            Error = e.getMessage();
            throw e;
        }
    }

Answer 1

http://expert.csdn.net/Expert/topic/1228/1228897.xml?temp=.5435907