是要按原来样式输出吗
高人教我用下面函数转换
public static String stoHTMLStr(String String1)
{
if( String1 == null )
return "";
else
{
int int2 = String1.length();
StringBuffer StringBuffer3 = new StringBuffer();
int int4; for( int4 = 0; int4 < int2; ++int4 )
{
char char5 = String1.charAt( int4 ); switch( char5 )
{
case 62:
StringBuffer3.append( ">" );
break;
case 60:
StringBuffer3.append( "<" );
break;
case 38:
StringBuffer3.append( "&" );
break;
case 32:
StringBuffer3.append( " " );
break;
case 10:
StringBuffer3.append( "<BR>" );
break;
default:
StringBuffer3.append( char5 );
break;
case 13:
break;
}
}
return StringBuffer3.toString();
}
}
高人教我用下面函数转换
public static String stoHTMLStr(String String1)
{
if( String1 == null )
return "";
else
{
int int2 = String1.length();
StringBuffer StringBuffer3 = new StringBuffer();
int int4; for( int4 = 0; int4 < int2; ++int4 )
{
char char5 = String1.charAt( int4 ); switch( char5 )
{
case 62:
StringBuffer3.append( ">" );
break;
case 60:
StringBuffer3.append( "<" );
break;
case 38:
StringBuffer3.append( "&" );
break;
case 32:
StringBuffer3.append( " " );
break;
case 10:
StringBuffer3.append( "<BR>" );
break;
default:
StringBuffer3.append( char5 );
break;
case 13:
break;
}
}
return StringBuffer3.toString();
}
}
解决方案 »
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