怎样在Tomcat环境下设置自己的虚拟路径

Question

modify server.xmllike this:
<Context path="/test" 
                   docBase="d:\\test" 
                   debug="0"    
                   reloadable="true">  
</Context>then reboot tomcat

Answer 1

应该是这样：
tomcat\conf\server.xml文件里 add:
<Context path="/test" docBase="d:\test" debug="0"
                 reloadable="true" crossContext="true">
          <Logger className="org.apache.catalina.logger.FileLogger"
                     prefix="localhost_examples_log." suffix=".txt"
           timestamp="true"/>
          <Ejb   name="ejb/EmplRecord" type="Entity"
                 home="com.wombat.empl.EmployeeRecordHome"
               remote="com.wombat.empl.EmployeeRecord"/>
</Context>
运行：http://localhost:8080/test/*.jsp

Answer 2

等我试验成功了，在加100分。话又说回来，刚学JSP才1天，以后放分的机会多着呢。

Answer 3

我用4.1.18,如下最新5.0
<Context path="" docBase="E:\test" debug="0"
                 reloadable="true" crossContext="true">
<Logger className="org.apache.catalina.logger.FileLogger"
                     prefix="localhost_examples_log." suffix=".txt"
           timestamp="true"/>
          <Ejb   name="ejb/EmplRecord" type="Entity"
                 home="com.wombat.empl.EmployeeRecordHome"
               remote="com.wombat.empl.EmployeeRecord"/>
</Context>
运行：http://localhost，port后的端口号随便改（8080为测试端口）
<Connector className="org.apache.coyote.tomcat4.CoyoteConnector"
port="80"               minProcessors="5" maxProcessors="75"
               enableLookups="true" redirectPort="8443"
               acceptCount="100" debug="0" connectionTimeout="20000"
               useURIValidationHack="false" disableUploadTimeout="true" />