请帮忙看看下面这段代码在jsp中怎么实现阿?

Question

String name;
while(request.getParameterNames().hasMoreElements()){
    name=request.getParameterNames().nextElement();
    out.println(request.getParameter(name));
}

Answer 1

请朋友们再看看，这段代码好像有错误阿Error: 500
Location: /cctv/test.jsp
Internal Servlet Error:org.apache.jasper.JasperException: Unable to compile class for JSPC:\jakarta_tomcat\work\localhost_8080%2Fcctv\_0002ftest_0002ejsptest_jsp_28.java:62: Incompatible type for =. Explicit cast needed to convert java.lang.Object to java.lang.String.
                {name=request.getParameterNames().nextElement();
                     ^
1 error at org.apache.jasper.compiler.Compiler.compile(Compiler.java:282)
at org.apache.jasper.servlet.JspServlet.doLoadJSP(JspServlet.java:612)
at org.apache.jasper.servlet.JasperLoader12.loadJSP(JasperLoader12.java:146)
at org.apache.jasper.servlet.JspServlet.loadJSP(JspServlet.java:542)
at org.apache.jasper.servlet.JspServlet$JspServletWrapper.loadIfNecessary(JspServlet.java:258)
at org.apache.jasper.servlet.JspServlet$JspServletWrapper.service(JspServlet.java:268)
at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:429)
at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:500)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
at org.apache.tomcat.core.ServletWrapper.doService(ServletWrapper.java:405)
at org.apache.tomcat.core.Handler.service(Handler.java:287)
at org.apache.tomcat.core.ServletWrapper.service(ServletWrapper.java:372)
at org.apache.tomcat.core.ContextManager.internalService(ContextManager.java:797)
at org.apache.tomcat.core.ContextManager.service(ContextManager.java:743)
at org.apache.tomcat.service.http.HttpConnectionHandler.processConnection(HttpConnectionHandler.java:213)
at org.apache.tomcat.service.TcpWorkerThread.runIt(PoolTcpEndpoint.java:416)
at org.apache.tomcat.util.ThreadPool$ControlRunnable.run(ThreadPool.java:501)
at java.lang.Thread.run(Thread.java:484)

Answer 2

name=String.valueOf(request.getParameterNames().nextElement());

Answer 3

sorry.
name=(String)request.getParameterNames().nextElement();

Answer 4

可是上面的while循环是无限的循环阿怎么才能实现真正的遍历呢

Answer 5

String name;
    Enumeration test=request.getParameterNames();
    while(test.hasMoreElements()){
        name=(String)test.nextElement();
        out.println(name+"="+request.getParameter(name));
        out.println("<br>");
    }

Answer 6

上面的死循环是由于重新引用了request.getParameterNames()