解决方案 »

  1.   

    if(排列四个){
            <br/>
    }
      

  2.   

    用s:iterator标签,判断index%4==0 换行
      

  3.   

    [#list tag_list as a]                       
                                  <td><table width="100%" border="0" cellpadding="0" cellspacing="0">
                                      <tr>
                                        <td><img src="/${res}/images/yszy/line3.gif" width="204" height="1" /></td>
                                      </tr>
                                      <tr>
                                       <td><table width="100%" border="0" cellpadding="0" cellspacing="0">
                                            <tr>
                                              <td width="1"><img src="/${res}/images/yszy/line4.gif" width="1" height="100" /></td>
                                              <td align="center" valign="top"><a href="${a.url!}"><img src="${a.titleImg!site.defImg}" alt="${a.title}" width="216" border="0" height="130"/></a><br>
                                               <p><span class="STYLE2"><a href="${a.url!}">${a.title}</a></span></p>
                                              </td> 
                                              <td width="1"><img src="/${res}/images/yszy/line4.gif" width="1" height="100" /></td>
                                            </tr>
                                        </table></td>
                                      </tr>
                                  </table></td>                              
                                   [/#list]是要把第十行的图片自动换行下,if条件写的具体一些! 谢谢啦!
      

  4.   

    s:iterator 好像有个step 属性 = 4 
     
      

  5.   

     <s:iterator value=list" status="st">
      <s:if test="#st.index%4==0 " >
    ........