到底要怎么才能在浏览器访问Servlet

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0"
    xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
  <servlet>

    <servlet-name>First</servlet-name>
    <servlet-class>web.First</servlet-class>
  </servlet>  <servlet-mapping>
    <servlet-name>First</servlet-name>
    <url-pattern>/servlet/First</url-pattern>
  </servlet-mapping></web-app>

package web;import java.io.IOException;
import java.io.PrintWriter;import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;public class First extends HttpServlet { /**
* Constructor of the object.
*/
public First() {
super();
} /**
* Destruction of the servlet. <br>
*/
public void destroy() {
super.destroy(); // Just puts "destroy" string in log
// Put your code here
} /**
* The doGet method of the servlet. <br>
*
* This method is called when a form has its tag value method equals to get.
*
* @param request the request send by the client to the server
* @param response the response send by the server to the client
* @throws ServletException if an error occurred
* @throws IOException if an error occurred
*/
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException { response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\">");
out.println("<HTML>");
out.println("  <HEAD><TITLE>A Servlet</TITLE></HEAD>");
out.println("  <BODY>");
out.print("    This is ");
out.print(this.getClass());
out.println(", using the GET method");
out.println("  </BODY>");
out.println("</HTML>");
out.flush();
out.close();
} /**
* The doPost method of the servlet. <br>
*
* This method is called when a form has its tag value method equals to post.
*
* @param request the request send by the client to the server
* @param response the response send by the server to the client
* @throws ServletException if an error occurred
* @throws IOException if an error occurred
*/
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException { response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\">");
out.println("<HTML>");
out.println("  <HEAD><TITLE>A Servlet</TITLE></HEAD>");
out.println("  <BODY>");
out.print("    This is ");
out.print(this.getClass());
out.println(", using the POST method");
out.println("  </BODY>");
out.println("</HTML>");
out.flush();
out.close();
} /**
* Initialization of the servlet. <br>
*
* @throws ServletException if an error occurs
*/
public void init() throws ServletException {
// Put your code here
}}

工程右键 export war 包到 tomcat 的webapps 下面，tomcat 启动成功
http://localhost:8080/webDemo/servlet/First 红色部分根据实际情况更改

Tomcat启动了吗？启动了以后浏览器输入-----localhost:8080/你的项目名/First
你的端口号是多少就把8080改成多少，如果你的 Web Context-root设置的是/，那就把上面的“你的项目名去掉”

把访问路径贴出来看看，是不是没加servlet

右键没有export war 这个选项

我访问我这个工程的index.jsp就能成功,但是访问Servlet就是无论如何都是无法成功的

代码没有问题，运行结果
This is class web.First, using the GET method
检查下自己的运行环境

把你的项目打成包，然后放tomact下

你要打成war包，放到tomcat的webapp目录下

项目右键export打成war包，放到tomcat的webapp目录下

你没有发布成功，看看你MYECLIPSE对应的TOMCAT目录下SERVLET的CLASS文件是否生成了，在MYECLIPSE里面重新发布一下

调试易

到底要怎么才能在浏览器访问Servlet

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