ajax json传值问题。求帮助

Question

你可以把两个对象封装成一个json对象在传

Answer 1

要传的对象直接在Action中声明 生成get set方法即可

Answer 2

我现在封装了。。可以传值了。。但是里面没值。。我action里面可以打印里面有值得啊

Answer 3

<action name="questionAjax_*" class="com.donen.action.ShowQuestionAction" method="{1}">
     <result type="json">
        <param name="root">
        jsonValues
        </param>
        <param name="includeProperties">
        questions,
        paging
        </param>
     </result>
  </action>这是我的配置
这是action
//分页辅助类
private Paging paging;
private List<Question> listQuestions ; 
private JsonValue jsonValues;
@JSON(serialize=false)
public JsonValue getJsonValues() {
return jsonValues;
}
public void setJsonValues(JsonValue jsonValues) {
this.jsonValues = jsonValues;
}//ajax获取下一页
public String nextPage(){
 System.out.println("come on $$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$");
 Integer currentPage =Integer.parseInt(request.getParameter("currentPage")) ;
 System.out.println(currentPage);
 paging = new Paging();
 paging.setCurrentPage(currentPage);
 paging.setPageSize(10);
String baseQu = "from Question q where q.device = '"+deviceId+"' order by q.date desc";
String nextString = APIUtile.CommonSql(url, "query",baseQu, baseQu,(currentPage=1).toString());
    System.out.println("$$$$$$$$$$$$"+nextString);
try {
JSONObject jsonObject = new JSONObject(nextString);
System.out.println("总记录数"+jsonObject.getInt("records"));
paging.setCountSize(jsonObject.getInt("records"));
jsonValues = new JsonValue();
if(jsonObject.getBoolean("success")){
listQuestions = PojoMapper.getObject(nextString, Question.class);
    System.out.println(listQuestions.size());
    jsonValues.setQuestions(listQuestions);
    jsonValues.setPaging(paging);
    System.out.println(jsonValues);
return SUCCESS;
}
} catch (JSONException e){
 System.out.println("出错啦"+e);
e.printStackTrace();
}
return SUCCESS;
}页面上获取时都没有值

Answer 4

你返回json  如这种 的。{"total":28,"rows":[
{"productid":"FI-SW-01","productname":"Koi","unitcost":10.00,"status":"P","listprice":36.50,"attr1":"Large","itemid":"EST-1"},
{"productid":"K9-DL-01","productname":"Dalmation","unitcost":12.00,"status":"P","listprice":18.50,"attr1":"Spotted Adult Female","itemid":"EST-10"},
{"productid":"RP-SN-01","productname":"Rattlesnake","unitcost":12.00,"status":"P","listprice":38.50,"attr1":"Venomless","itemid":"EST-11"},
{"productid":"RP-SN-01","productname":"Rattlesnake","unitcost":12.00,"status":"P","listprice":26.50,"attr1":"Rattleless","itemid":"EST-12"},
{"productid":"RP-LI-02","productname":"Iguana","unitcost":12.00,"status":"P","listprice":35.50,"attr1":"Green Adult","itemid":"EST-13"},
{"productid":"FL-DSH-01","productname":"Manx","unitcost":12.00,"status":"P","listprice":158.50,"attr1":"Tailless","itemid":"EST-14"},
{"productid":"FL-DSH-01","productname":"Manx","unitcost":12.00,"status":"P","listprice":83.50,"attr1":"With tail","itemid":"EST-15"},
{"productid":"FL-DLH-02","productname":"Persian","unitcost":12.00,"status":"P","listprice":23.50,"attr1":"Adult Female","itemid":"EST-16"},
{"productid":"FL-DLH-02","productname":"Persian","unitcost":12.00,"status":"P","listprice":89.50,"attr1":"Adult Male","itemid":"EST-17"},
{"productid":"AV-CB-01","productname":"Amazon Parrot","unitcost":92.00,"status":"P","listprice":63.50,"attr1":"Adult Male","itemid":"EST-18"}
]}

Answer 5

你浏览器直接敲你的 action 地址，看看是不是返回json 的数据。

Answer 6

我json里面有参数但是参数没有值

Answer 7

你map 里面放好。用开源jar 转json 。
然后就可以阿。
看看这个url

Answer 8

我不懂啊。。没用过呢。。放list里面不行么？

Answer 9

我也遇到过内饰的json结构的要求，采用的是 利用List集合和DTO解决的

Answer 10

好。我回去试试。。现在先不用ajax了