做了一个小的登录程序，运行的时候跳出这样的错误，有熟悉的人帮我看看呢

Question

javax.servlet.jsp.JspException: No getter method for property: "username" of bean: "org.apache.struts.action.DynaActionForm"
at org.apache.struts.taglib.TagUtils.lookup(TagUtils.java:987)
at org.apache.struts.taglib.html.BaseFieldTag.prepareValue(BaseFieldTag.java:121)
at org.apache.struts.taglib.html.BaseFieldTag.renderInputElement(BaseFieldTag.java:102)
at org.apache.struts.taglib.html.BaseFieldTag.doStartTag(BaseFieldTag.java:81)
at org.apache.jsp.WEB_002dINF.form.userlogin_jsp._jspx_meth_html_text_0(userlogin_jsp.java:204)
at org.apache.jsp.WEB_002dINF.form.userlogin_jsp._jspx_meth_html_form_0(userlogin_jsp.java:147)
at org.apache.jsp.WEB_002dINF.form.userlogin_jsp._jspService(userlogin_jsp.java:96)
at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:97)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:334)
at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:252)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:173)
at org.apache.catalina.core.ApplicationDispatcher.invoke(ApplicationDispatcher.java:672)
at org.apache.catalina.core.ApplicationDispatcher.processRequest(ApplicationDispatcher.java:463)
at org.apache.catalina.core.ApplicationDispatcher.doForward(ApplicationDispatcher.java:398)
at org.apache.catalina.core.ApplicationDispatcher.forward(ApplicationDispatcher.java:301)
at org.apache.jasper.runtime.PageContextImpl.doForward(PageContextImpl.java:688)
at org.apache.jasper.runtime.PageContextImpl.forward(PageContextImpl.java:658)
at org.apache.struts.taglib.logic.ForwardTag.doForward(ForwardTag.java:121)
at org.apache.struts.taglib.logic.ForwardTag.doEndTag(ForwardTag.java:105)
at org.apache.jsp.index_jsp._jspx_meth_logic_forward_0(index_jsp.java:105)
at org.apache.jsp.index_jsp._jspService(index_jsp.java:78)
at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:97)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:334)
at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:252)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:173)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:213)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:178)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:126)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:105)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:107)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:148)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:869)
at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:664)
at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:527)
at org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(LeaderFollowerWorkerThread.java:80)
at org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:684)
at java.lang.Thread.run(Thread.java:595)
PropertyMessageResources - getMessage(zh_CN,forward.forward)
[jsp] - Servlet.service() for servlet jsp threw exception
javax.servlet.jsp.JspException: Exception forwarding for name userlogin: org.apache.jasper.JasperException: Exception in JSP: /WEB-INF/form/userlogin.jsp:5653:  <B>鐢? 鎴? 鍚?:</B>
54:  </TD>
55:  <TD width="30%">
56:  <html:text property="username"/>
57:  </TD>
58:  <TD width="20%">
59:  &nbsp;

Answer 1

<%@ page language="java" pageEncoding="UTF-8"%><%@ taglib uri="http://struts.apache.org/tags-bean" prefix="bean"%>
<%@ taglib uri="http://struts.apache.org/tags-html" prefix="html"%>
<%@ taglib uri="http://struts.apache.org/tags-logic" prefix="logic"%>
<%@ taglib uri="http://struts.apache.org/tags-tiles" prefix="tiles"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<HTML>
<HEAD>
<TITLE>登陆页</TITLE>
<META http-equiv=Content-Type content="text/html; charset=utf-8">
<LINK href="./css/user.css" type=text/css rel=stylesheet>
<LINK href="./css/bbs1.css" type=text/css rel=stylesheet>
<SCRIPT language=javaScript src="./css/Main.js" type=text/javascript></SCRIPT> <META content="MSHTML 6.00.3790.3959" name=GENERATOR>
<script type="text/javascript">
function check()
{
if(document.all["username"].value=="")
{
alert("请输入登陆名.");
return false;
}
else if(document.all["password"].value=="")
{
alert("请输入登陆密码");
return false;
}
return true;
}
</script>
</HEAD>
<BODY leftMargin=0 topMargin=0 marginheight="0" marginwidth="0">

<html:form action="/userlogin" method="post" focus="username" onsubmit="return check();">
<TABLE class=tableBorder cellSpacing=0 cellPadding=0 width="95%"
align=center>
<TBODY>
<TR>
<TH class=th width="35%" colSpan=4 height=25>
<SPAN>登 陆<SPAN></SPAN>
</SPAN>
</TH>
</TR>
<TR>
<TD width="20%">
&nbsp;
</TD>
<TD width="30%" height=25>
<B>用 户 名:</B>
</TD>
<TD width="30%">
<html:text property="username"/>
</TD>
<TD width="20%">
&nbsp;
</TD>
</TR>
<TR>
<TD width="20%">
&nbsp;
</TD>
<TD width="30%" height=25>
<B>用户密码:</B>
</TD>
<TD width="30%">
<html:password property="password"/>
</TD>
<TD width="20%">
&nbsp;
</TD>
</TR>
<TR style="TEXT-ALIGN: center">
<TH class=th width="35%" colSpan=4 height=25>
<INPUT type=submit value=登陆>
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;
<INPUT type=reset value=重置>
</TH>
</TR>
</TBODY>
</TABLE>
</html:form>
</BODY>
</HTML>
文件是这样写的

Answer 2

后台Action是怎么写的，把代码贴出来。

Answer 3

谢谢各位的帮助，action 为下/*
 * Generated by MyEclipse Struts
 * Template path: templates/java/JavaClass.vtl
 */
package com.hanke.struts.action;import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import org.apache.struts.action.DynaActionForm;
import java.io.IOException;import javax.servlet.http.HttpSession;
import org.apache.struts.actions.DispatchAction;
import com.hanke.service.biz.IuserBiz;
import com.hanke.service.entity.user;
/** 
 * MyEclipse Struts
 * Creation date: 07-27-2011
 * 
 * XDoclet definition:
 * @struts.action path="/userlogin" name="userloginForm" input="/WEB-INF/form/userlogin.jsp" scope="request" validate="true"
 */
public class UserloginAction extends Action {

    private IuserBiz userBiz;
  
public IuserBiz getUserBiz() {
return userBiz;
}   public void setUserBiz(IuserBiz userBiz) {
this.userBiz = userBiz;
} public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response) {
DynaActionForm userloginForm = (DynaActionForm) form;// TODO Auto-generated method stub
DynaActionForm dform = (DynaActionForm)form;
String username = (String)dform.get("username");
String password = (String)dform.get("password");
// 调用商业组件进行用户身份验证
user user = userBiz.verifyUser(username, password);
if (user != null) {
request.getSession().setAttribute("CURRENT_USER", username);
// 成功登陆，在会话监听器集合中更新登陆状态

request.setAttribute("msg", user.getUsername());

mapping.findForward("welcome");
} else {
request.setAttribute("msg", "用户名或密码错误，登陆失败！");
}

return null;
}
}

Answer 4

DynaActionForm 里没username这个属性或少了GET,SET方法。

Answer 5

javax.servlet.jsp.JspException: No getter method for property: "username" of bean: "org.apache.struts.action.DynaActionForm"DynaActionForm 里没username这个属性或少了GET,SET方法。 
检查下form文件
 

Answer 6

这个类里面的这个属性没用getset方法

Answer 7

用的是代理的Form还是自己定义的Form，如果是自己定义的Form就要检查一下UserloginForm了

Answer 8

DynaActionForm  里面的 username 没有生成 get、set 方法