我使用一个拦截器验证用户是否登录，如果没有登录if（session.get("user")==null){return Action.LOGIN;}，result的地址转向login(<result name="login">/login.jsp</result>，url地址是http://localhost:8080/struts2/struts/login.action。我现在的问题是：转到登录页面后为什么我在这个（http://localhost:8080/struts2/struts/login.action）页面上输入用户密码提交后，会出404错误。这是为什么？如何解决？
package myinterceptor;
import com.opensymphony.xwork2.interceptor.Interceptor;
import com.opensymphony.xwork2.ActionInvocation;
import java.util.*;
public class MyInterceptor implements Interceptor{
public String intercept(ActionInvocation invocation)throws Exception{
Map<?,?> session=invocation.getInvocationContext().getSession();
if(session.get("user")==null){
return com.opensymphony.xwork2.Action.LOGIN;
}
return invocation.invoke();
}
public void init(){
}
public void destroy() { }
}Action代码：
package myinterceptor;
import com.opensymphony.xwork2.ActionSupport;
import com.opensymphony.xwork2.ActionContext;
public class ActionAndInterceptor extends ActionSupport{
private String user;
private String password;
public String getUser() {
return user;
}
public void setUser(String user) {
this.user = user;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String execute()throws Exception{
return SUCCESS;
}
public void validate(){
if(user.equals("myname")&password.equals("mypassword")){
ActionContext.getContext().getSession().put("user", user);
}else{
addFieldError("user",getText("login"));
}
}
}package myinterceptor;
import com.opensymphony.xwork2.ActionSupport;
public class MyAction extends ActionSupport{
public String execute()throws Exception{
return SUCCESS;
}
}struts.xml代码：
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN" "http://struts.apache.org/dtds/struts-2.1.dtd">
<struts>
<package name="m" namespace="/myinterceptor" extends="struts-default">
<interceptors >
<interceptor name="my" class="myinterceptor.MyInterceptor"/>
<interceptor-stack name="my">
<interceptor-ref name ="my" />
<interceptor-ref name="defaultStack"/>
</interceptor-stack>
</interceptors >
<action name="MyAction" class="myinterceptor.MyAction">
<interceptor-ref name="my"/>
<result name="success">/myinterceptor/MyJsp.jsp</result>
<result name="input">/index.jsp</result>
<result name="login">/index.jsp</result>
</action>
<action name="ActionAndInterceptor" class="myinterceptor.ActionAndInterceptor">
<result name="success">/myinterceptor/result.jsp</result>
<result name="input">/index.jsp</result>
</action>
</package>
</struts>
JSP：index.jsp
<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%@ taglib prefix="s" uri="/struts-tags"%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
</head>
<body>
<s:form action="myinterceptor/ActionAndInterceptor.action">
<s:textfield name="user" label="user"/>
<s:textfield name="password" label="password"/>
<s:submit/>
</s:form>
</body>
</html>我首先进入index.jsp页面登录输入用户名和密码，可以运行MyAction 但是我先http://localhost:8080/struts2/myinterceptor/MyAction.action这个时，会显示index.jsp页面，然后输入用户名和密码点提交就会出错
重定向跳转到login页面，那么你显示的地址就是http://localhost:8080/struts2/struts/login.jsp,你可以再尝试一下行不行，如果还不行的话可以将代码发给我，相互交流一下.