我用jquery调用后台的代码(struts)
js代码:
<script type="text/javascript" src="js/jquery-1.2.2.js"></script>
<script type="text/javascript">
function check()
{
var name=$("#n").val();
var methodName="findBName";
url="book.do?meth="+methodName;
$.get(url,name,callback);
}
function callback(data)
{
var rel=$("#result");
alert(data);
}后台代码:
public Object findBName(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response)
throws Exception
{
User user=(User) request.getSession().getAttribute("user");
String name=request.getParameter("name");
Object relationid=ibb.findBName(user.getUserId(),name);
return relationid.toString();
}为啥接收不到findBName()返回的结果啊?
js代码:
<script type="text/javascript" src="js/jquery-1.2.2.js"></script>
<script type="text/javascript">
function check()
{
var name=$("#n").val();
var methodName="findBName";
url="book.do?meth="+methodName;
$.get(url,name,callback);
}
function callback(data)
{
var rel=$("#result");
alert(data);
}后台代码:
public Object findBName(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response)
throws Exception
{
User user=(User) request.getSession().getAttribute("user");
String name=request.getParameter("name");
Object relationid=ibb.findBName(user.getUserId(),name);
return relationid.toString();
}为啥接收不到findBName()返回的结果啊?
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HttpServletRequest request, HttpServletResponse response)
throws Exception {
PrintWriter out = response.getWriter();
String flag = "false";
out.print(flag);
out.flush();
out.close();
return null;
}
你可以把你的Object转为JsonObject
用它的构造方法就可以了
JSONObject(java.lang.Object bean)
Construct a JSONObject from an Object using bean getters.
out.write(relationid.toString());试试