http上传图片的问题

Question

不是，可以用apache的fileupoload

Answer 1

获取上传文件的代码片段：
String temp=request.getSession().getServletContext().getRealPath("/")+"temp";   //临时目录
        System.out.println("temp="+temp);
        String loadpath=request.getSession().getServletContext().getRealPath("/")+"Image"; //上传文件存放目录
        File tempFile=new File(temp);
        File loadPathFile=new File(loadpath);
        if(!tempFile.exists()){
         tempFile.mkdirs();
        }
        if(!loadPathFile.exists()){
         loadPathFile.mkdirs();
        }
        System.out.println("loadpath="+loadpath);
        DiskFileUpload fu = new DiskFileUpload();
        fu.setSizeMax(1*1024*1024);   // 设置允许用户上传文件大小,单位:字节 
        fu.setSizeThreshold(4096);   // 设置最多只允许在内存中存储的数据,单位:字节 
        fu.setRepositoryPath(temp); // 设置一旦文件大小超过getSizeThreshold()的值时数据存放在硬盘的目录 
        
        //开始读取上传信息 
        int index=0;
        List fileItems = null;
             
                      
                             try {
                                     fileItems = fu.parseRequest(request);
                                      System.out.println("fileItems="+fileItems);
                             } catch (Exception e) {
                                     e.printStackTrace();
                             }
                      
             
        Iterator iter = fileItems.iterator(); // 依次处理每个上传的文件
        while (iter.hasNext())
        {
            FileItem item = (FileItem)iter.next();// 忽略其他不是文件域的所有表单信息
            if (!item.isFormField())
            {
                String name = item.getName();//获取上传文件名,包括路径
                System.out.println("111111111name:"+name);
                name=name.substring(name.lastIndexOf("\\")+1);//从全路径中提取文件名
                long size = item.getSize();
                if((name==null||name.equals("")) && size==0) 
                      continue; 
                int point = name.indexOf(".");
                name=(new Date()).getTime()+name.substring(point,name.length());
                System.out.println("222222222222name:"+name);
                index++;
                File fNew= new File(loadpath, name);
                try {
                                     item.write(fNew);
                             } catch (Exception e) {
                                     // TODO Auto-generated catch block
                                     e.printStackTrace();
                             }
                
               
            }使用fileupoload可以保存上传的文件，但是我想知道的是在客户端使用reqEntity.addPart("comment", comment);这个的key的意义何在？