如何判断字符之间相差几个级别？

Question

我是JSP新手，这里有十个级别的字符串，如何判断任意两个之间相差几个级别？
级别字符为："AAA","AA","A","BBB","BB","B""CCC","CC",,"C","D"

Answer 1

用map啊。
字符串key,级别是value。

Answer 2

public class Test12 {
public static void main(String args[]){
String s1 = "BB";
String s2 = "C";
level(s1,s2);   //你可以任意设定字符串数组中存在的s1，s2
}

public static void level(String s1,String s2){
String[] s = {"AAA","AA","A","BBB","BB","B","CCC","CC","C","D"};
int i = 0,j = 0; 
for(; i < s.length; i++)
if(s1.equalsIgnoreCase(s[i]))
break;
for(; j < s.length; j++)
if(s2.equalsIgnoreCase(s[j]))
break;
System.out.println("The level between " + s1 + " and " + s2 + " is " + String.valueOf(j - i));
}
}