我的过滤器的dofilter方法如下public void doFilter(ServletRequest request, ServletResponse response,
FilterChain chain) throws IOException, ServletException {
// TODO Auto-generated method stub
String path=((HttpServletRequest)request).getRequestURI();
System.out.println("Filter:"+path);
chain.doFilter(request, response);
}
我发现如果不加上chain.doFilter(request, response),则请求不会得到任何响应但加上后,会自动交给web。xml里写的servlet去处理。我现在想根据path的不同把请求交给不同的servlet去处理,该怎么写?
FilterChain chain) throws IOException, ServletException {
// TODO Auto-generated method stub
String path=((HttpServletRequest)request).getRequestURI();
System.out.println("Filter:"+path);
chain.doFilter(request, response);
}
我发现如果不加上chain.doFilter(request, response),则请求不会得到任何响应但加上后,会自动交给web。xml里写的servlet去处理。我现在想根据path的不同把请求交给不同的servlet去处理,该怎么写?
<servlet-name>OrderMock</servlet-name>[code=XML]
<servlet-class>com.temobi.misc.wbsc.service.OrderMock</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>OrderMock</servlet-name>
<url-pattern>/test/provision.mock</url-pattern>
</servlet-mapping>
[/code]
来配置
<filter>
<filter-name>filter</filter-name>
<filter-class>完整类名</filter-class>
</filter>
<filter-mapping>
<filter-name>filter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
web容器是不会理会没有配置的servlet的