urlrewrite正则匹配多个参数（急！高手支招）

Question

urlrewrite.xml中配置<urlrewrite>
    <rule>  
        <from>^/blog/([0-1])/([0-9a-zA-Z]+).shtml$</from>  
        <to type="forward">blog.do?language=$1</to>  
    </rule>
</urlrewrite>我想要的是路径http://localhost:8080/test/blog/0/a9a89a8s9oouio23oosdf.shtml 
转到 http://localhost:8080/test/blog.do?language=0&article=a9a89a8s9oouio23oo
劳请高手支招 谢谢

Answer 1

<rule> 
    <note/> 
    <from>^/blog/([0-9]\d{0,3}+)/([0-9a-zA-Z]{0,32}+).shtml/?$ </from>  
    <to type="forward">/blog.do?language=$1&amp;article=$2 </to> 
  </rule> 

Answer 2

<urlrewrite> 
    <rule>  
        <from>^/blog/([0-1])/([0-9a-zA-Z]+).shtml$ </from>  
        <to type="forward">^/blog.do?language=$1&amp;article=$2 </to>  
    </rule> 
</urlrewrite> 
test配成根站点吧 不要test了好好学习 天天向上

Answer 3

对不起，
写错了
<urlrewrite> 
    <rule>  
        <from>^/blog/([0-1])/([0-9a-zA-Z]+).shtml$ </from>  
        <to type="forward">/blog.do?language=$1&amp;article=$2 </to>  
    </rule> 
</urlrewrite>