页面提交后不能显示“提交成功”信息，控制台也不能输出字符串，求指导

做v512工作室的2009博客项目遇到了一个问题，当点击提交博客后，不能进入新的、显示有“提交成功”或者“提交失败”网页，现在它仅仅显示一个纯的、空白的页面。
为了弄清原因，我在sevlet中临时增加了控制台输出的程序，发现除result值和category_id值能够正确输出以外，其余的都没有显示。
数据库用的是MySQL，提交的博客能够正常存储。
以下是BlogServlet.java和的addBlogResult.jsp代码，希望大家能帮帮我~BlogServlet.java:package com.miffy.blog;import java.io.IOException;
import java.io.PrintWriter;
import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.SQLException;import javax.naming.Context;
import javax.naming.InitialContext;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.sql.DataSource;public class BlogServlet extends HttpServlet {
private static final long serialVersionUID = 1L;

public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
doPost(request, response); } public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
// 解决从JSP页面接受中文参数乱码
request.setCharacterEncoding("UTF-8");

String title = request.getParameter("title");
String content = request.getParameter("content");
String categoryId = request.getParameter("category");

System.out.println(title);
System.out.println(content);
System.out.println(categoryId);

DataSource ds = null;

try {
Context  context = new InitialContext();
ds = (DataSource) context.lookup("java:/comp/env/jdbc/mysqlds");
} catch (Exception e) {
System.out.println("--获取数据源时出错--");
}

int result = 0;

try {
Connection conn = ds.getConnection();
String sql = "insert into blog (title,content,category_id,created_time) values(?,?,?,now())";
PreparedStatement pstmt = conn.prepareStatement(sql);
pstmt.setString(1, title);
pstmt.setString(2, content);
pstmt.setInt(3, Integer.parseInt(categoryId));

result = pstmt.executeUpdate();
System.out.println("begins now");
System.out.println(result);
System.out.println("begins now");
} catch (SQLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}

String mess = "begins now";
System.out.println("begins now");
System.out.println(2 + 1);
System.out.println(mess);
String message = "default";
System.out.println(message);
if(result == 1) {
message = "添加博文成功！";
} else {
message = "添加博文失败";
}

System.out.println(message);
request.setAttribute("message", message);
request.getRequestDispatcher("/addBlogResult.jsp").forward(request, response);
}}addBlogResult.jsp:
<%@ page language="java" import="java.util.*" pageEncoding="ISO-8859-1"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
    <base href="<%=basePath%>">

    <title>My JSP 'addBlogResult.jsp' starting page</title>

<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
  </head>

  <body>
    <h3> <%=request.getAttribute("message") %> <br></h3>
  </body>
</html>

解决方案 »

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try {
  Context  context = new InitialContext();
                        ds = (DataSource) context.lookup("java:/comp/env/jdbc/mysqlds");
                    }                       catch (Exception e) {   System.out.println("--获取数据源时出错--");

此处你并没有捕获异常信息。捕获异常试试下。
说实话我JNDI没怎么用过、我都是用jdbc连接

}
你在Connection conn = ds.getConnection();
上面打印一条字符串试试。个人查了查百度等博主关于judi信息
http://5211422.iteye.com/blog/315704 ds = (DataSource) context.lookup("java:/comp/env/jdbc/mysqlds");
个人感觉这地方出错。
楼主捕获一下异常，看有没有错误，
ds = (DataSource)ctx.lookup("java:comp/env/jdbc/ds");
楼主是不是写错了！
断点试试，有没有报什么错，页面的编码格式改成UTF-8