一个项目要求在EJB中访问一个特定的url并传递参数,就像这样 http://xxx.xxx.xxx.xxx:xx/abc.php?action=activate&uid=.....,得到响应后读取响应正文(不是Http头)的内容,正文大概是这样:status=succed\n date=.....\n .....,我用HttpURLConnection不知道是否可以,有更高效的办法吗,能给我一段HttpURLConnection的实例代码吗
调试欢乐多
public static void main(String[] args) throws Exception {
URL theURL = new URL("http://blog.csdn.net/sunyujia/");
URLConnection urlConnection = theURL.openConnection();
urlConnection.connect();
// System.out.println(urlConnection.getContentType());
// BufferedReader in = new BufferedReader(new
// InputStreamReader(urlConnection.getInputStream()));
// StringWriter swr = new StringWriter();
// PrintWriter sw = new PrintWriter(swr, true);
// for (String line; (line = in.readLine()) != null;) {
// sw.println(line);
// }
// System.out.println(swr.toString());
// in.close(); InputStream in = urlConnection.getInputStream();
ByteArrayOutputStream bos = new ByteArrayOutputStream();
int bufferSize = 1024 * 1024;
byte[] buffer = new byte[bufferSize];// 缓冲区
for (int bytesRead = 0; (bytesRead = in.read(buffer)) != -1;) {
bos.write(buffer, 0, bytesRead);
Arrays.fill(buffer, (byte) 0);
}
System.out.println(new String(bos.toByteArray(), "UTF-8"));
in.close();
}