该代码段能正常显示所有记录,但按姓名查或按职称(下拉式列表)或按部门(下拉式列表)时均查不到记录,请问代码该如何修改呢?另外”修改“两个字怎么不是超链接的样式? String sqlString=" ";
String teacherName=request.getParameter("teacherName");
String technicalPosition=request.getParameter("technicalPositionSelect");
String department=request.getParameter("departmentSelect");
if(request.getParameter("teacherName")!=null && request.getParameter("teacherName")!="")
{
sqlString=sqlString+ "and T_name='teacherName'";
}
if(request.getParameter("technicalPositionSelect")!=null&&request.getParameter("technicalPositionSelect")!="")
{
sqlString=sqlString + " and T_technicalposition='technicalPosition'";
}
if(request.getParameter("departmentSelect")!=null&&request.getParameter("departmentSelect")!="")
{
sqlString=sqlString + " and T_department='department'";
}
ResultSet rs=db.executeQuery("select * from teacher "
+" where 1=1 "
+sqlString+" order by T_name desc "
String teacherId="";
while(rs.next())
{
teacherId=rs.getString("Id");
out.println("<tr height=22>");
out.println("<td align=center>"+rs.getString("T_name")+"</td>");
out.println("<td align=center>"+rs.getString("T_technicalposition")+"</td>");
out.println("<td align=center>"+rs.getString("T_department")+"</td>");
%>
<td align="center"<a href="teacherModify.jsp?teacherId=<%=teacherId%>">
修改</a> <a href="javascript:del('teacherManage.jsp',<%=teacherId%>)">删除</a></td></tr>
}
String teacherName=request.getParameter("teacherName");
String technicalPosition=request.getParameter("technicalPositionSelect");
String department=request.getParameter("departmentSelect");
if(request.getParameter("teacherName")!=null && request.getParameter("teacherName")!="")
{
sqlString=sqlString+ "and T_name='teacherName'";
}
if(request.getParameter("technicalPositionSelect")!=null&&request.getParameter("technicalPositionSelect")!="")
{
sqlString=sqlString + " and T_technicalposition='technicalPosition'";
}
if(request.getParameter("departmentSelect")!=null&&request.getParameter("departmentSelect")!="")
{
sqlString=sqlString + " and T_department='department'";
}
ResultSet rs=db.executeQuery("select * from teacher "
+" where 1=1 "
+sqlString+" order by T_name desc "
String teacherId="";
while(rs.next())
{
teacherId=rs.getString("Id");
out.println("<tr height=22>");
out.println("<td align=center>"+rs.getString("T_name")+"</td>");
out.println("<td align=center>"+rs.getString("T_technicalposition")+"</td>");
out.println("<td align=center>"+rs.getString("T_department")+"</td>");
%>
<td align="center"<a href="teacherModify.jsp?teacherId=<%=teacherId%>">
修改</a> <a href="javascript:del('teacherManage.jsp',<%=teacherId%>)">删除</a></td></tr>
}
楼主【hyxwxy】截止到2008-07-25 17:00:19的历史汇总数据(不包括此帖):
发帖的总数量:15 发帖的总分数:220 每贴平均分数:14
回帖的总数量:24 得分贴总数量:2 回帖的得分率:8%
结贴的总数量:13 结贴的总分数:200
无满意结贴数:0 无满意结贴分:0
未结的帖子数:2 未结的总分数:20
结贴的百分比:86.67 % 结分的百分比:90.91 %
无满意结贴率:0.00 % 无满意结分率:0.00 %
楼主加油
超连接不要放TD里或者换下条件,这么写
teacherName!=null&&teacherName.length()>0
错了
<td align="center"><a href="teacherModify.jsp?teacherId=<%=teacherId%>">修改</a>查不出来的原因是因为你这个sqlString初值是不是有个空格?所以最后的sql不正确了。
你在执行前把这句SQL打出来看看,可能拼错了。dubug一下吧。还有楼主的头像挺不错,我喜欢,呵呵。
或者数据库中没有符合的记录。
String teacherName=request.getParameter("teacherName");
String technicalPosition=request.getParameter("technicalPositionSelect");
String department=request.getParameter("departmentSelect");
if(request.getParameter("teacherName")!=null && request.getParameter("teacherName")!="")
{
sqlString=sqlString+ "and T_name='teacherName'";
}
if(request.getParameter("technicalPositionSelect")!=null&&request.getParameter("technicalPositionSelect")!="")
{
sqlString=sqlString + " and T_technicalposition='technicalPosition'";
}
if(request.getParameter("departmentSelect")!=null&&request.getParameter("departmentSelect")!="")
{
sqlString=sqlString + " and T_department='department'";
}
//你把这个sqlString的值复制下来放到你的数据库里去执行一下看看效果就知道了。
sqlString = "select * from teacher where 1=1 " + sqlString + "orderby T_name desc";
ResultSet rs=db.executeQuery(sqlString);
String sqlString="";
String teacherName=request.getParameter("teacherName");
String technicalPosition=request.getParameter("technicalPositionSelect");
String department=request.getParameter("departmentSelect");
if(request.getParameter("teacherName")!=null && request.getParameter("teacherName")!="") {
sqlString=sqlString+ "and T_name='teacherName' ";
}
if(request.getParameter("technicalPositionSelect")!=null&&request.getParameter("technicalPositionSelect")!="") {
sqlString=sqlString + "and T_technicalposition='technicalPosition' ";
}
if(request.getParameter("departmentSelect")!=null&&request.getParameter("departmentSelect")!="") {
sqlString=sqlString + "and T_department='department' ";
} //你把这个sqlString的值复制下来放到你的数据库里去执行一下看看效果就知道了。
sqlString = "select * from teacher where 1=1 " + sqlString + "order by T_name desc";
ResultSet rs=db.executeQuery(sqlString);
拿我这个试试看,呵呵。将结果告诉我。