CREATE FUNCTION GET_STRING(@name VARCHAR(50)) RETURNS VARCHAR(50) AS BEGIN DECLARE @CLASS VARCHAR(50) SELECT @CLASS=ISNULL(@CLASS+' ','')+res FROM tB WHERE name=@name order by name RETURN @CLASS END
如何用select 实现??05以上可以
/* 标题:按某字段合并字符串之一(简单合并) 作者:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开) 时间:2008-11-06 地点:广东深圳描述:将如下形式的数据按id字段合并value字段。 id value ----- ------ 1 aa 1 bb 2 aaa 2 bbb 2 ccc 需要得到结果: id value ------ ----------- 1 aa,bb 2 aaa,bbb,ccc 即:group by id, 求 value 的和(字符串相加) */ --1、sql2000中只能用自定义的函数解决 create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') gocreate function dbo.f_str(@id int) returns varchar(100) as begin declare @str varchar(1000) set @str = '' select @str = @str + ',' + cast(value as varchar) from tb where id = @id set @str = right(@str , len(@str) - 1) return @str end go--调用函数 select id , value = dbo.f_str(id) from tb group by iddrop function dbo.f_str drop table tb --2、sql2005中的方法 create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') goselect id, [value] = stuff((select ',' + [value] from tb t where id = tb.id for xml path('')) , 1 , 1 , '') from tb group by iddrop table tb --3、使用游标合并数据 create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go declare @t table(id int,value varchar(100))--定义结果集表变量 --定义游标并进行合并处理 declare my_cursor cursor local for select id , value from tb declare @id_old int , @id int , @value varchar(10) , @s varchar(100) open my_cursor fetch my_cursor into @id , @value select @id_old = @id , @s='' while @@FETCH_STATUS = 0 begin if @id = @id_old select @s = @s + ',' + cast(@value as varchar) else begin insert @t values(@id_old , stuff(@s,1,1,'')) select @s = ',' + cast(@value as varchar) , @id_old = @id end fetch my_cursor into @id , @value END insert @t values(@id_old , stuff(@s,1,1,'')) close my_cursor deallocate my_cursorselect * from @t drop table tb
---------------------------------------------------------------- -- Author :fredrickhu(小F,向高手学习) -- Date :2010-01-05 17:18:03 -- Version: -- Microsoft SQL Server 2005 - 9.00.4035.00 (Intel X86) -- Nov 24 2008 13:01:59 -- Copyright (c) 1988-2005 Microsoft Corporation -- Developer Edition on Windows NT 5.1 (Build 2600: Service Pack 3) -- ---------------------------------------------------------------- --> 测试数据:[tb] if object_id('[tb]') is not null drop table [tb] go create table [tb]([id] int,[value] varchar(1)) insert [tb] select 1,'a' union all select 1,'b' union all select 2,'x' union all select 2,'y' union all select 2,'z' --------------开始查询-------------------------- select id, [values]=(select ''+[value] from tb t where id=tb.id for xml path('')) from tb group by id ----------------结果---------------------------- /*id values ----------- ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- 1 ab 2 xyz(2 行受影响) */
合并列值 --******************************************************************************************* 表结构,数据如下: id value ----- ------ 1 aa 1 bb 2 aaa 2 bbb 2 ccc 需要得到结果: id values ------ ----------- 1 aa,bb 2 aaa,bbb,ccc 即:group by id, 求 value 的和(字符串相加) 1. 旧的解决方法(在sql server 2000中只能用函数解决。) --============================================================================= create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go --1. 创建处理函数 CREATE FUNCTION dbo.f_strUnite(@id int) RETURNS varchar(8000) AS BEGIN DECLARE @str varchar(8000) SET @str = '' SELECT @str = @str + ',' + value FROM tb WHERE id=@id RETURN STUFF(@str, 1, 1, '') END GO -- 调用函数 SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id drop table tb drop function dbo.f_strUnite go /* id value ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc (所影响的行数为 2 行) */ --=================================================================================== 2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。) create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go -- 查询处理 SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY( SELECT [values]= STUFF(REPLACE(REPLACE( ( SELECT value FROM tb N WHERE id = A.id FOR XML AUTO ), ' <N value="', ','), '"/>', ''), 1, 1, '') )N drop table tb /* id values ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc (2 行受影响) */ --SQL2005中的方法2 create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '') from tb group by id /* id values ----------- -------------------- 1 aa,bb 2 aaa,bbb,ccc (2 row(s) affected) */ drop table tb
--sql 2000只能用函数实现,SQL 2005见二楼帖. create table tb (a1 int, a2 varchar(10)) insert into tb values(1 ,'a') insert into tb values(1 ,'b') insert into tb values(2 ,'x') insert into tb values(2 ,'y') insert into tb values(2 ,'z') go create function dbo.f_str(@a1 int) returns varchar(100) as begin declare @str varchar(1000) set @str = '' select @str = @str + cast(a2 as varchar) from tb where a1 = @a1 return @str end go--调用函数 select a1 , a2 = dbo.f_str(a1) from tb group by a1drop function dbo.f_str drop table tb /* a1 a2 ----------- ---------------------------------------------------------------------------------------------------- 1 ab 2 xyz(所影响的行数为 2 行)*/
---------------------------------------------------------------- -- Author :SQL77(只为思齐老) -- Date :2010-01-05 17:19:25 -- Version: -- Microsoft SQL Server 2000 - 8.00.194 (Intel X86) -- Aug 6 2000 00:57:48 -- Copyright (c) 1988-2000 Microsoft Corporation -- Desktop Engine on Windows NT 5.1 (Build 2600: Service Pack 3) -- ---------------------------------------------------------------- --> 测试数据:[A] if object_id('[A]') is not null drop table [A] go create table [A]([a1] int,[a2] varchar(1)) insert [A] select 1,'a' union all select 1,'b' union all select 2,'x' union all select 2,'y' union all select 2,'z' --------------开始查询-------------------------- alter FUNCTION GET_STRING(@a1 int) RETURNS VARCHAR(50) AS BEGIN DECLARE @CLASS VARCHAR(50) SELECT @CLASS=ISNULL(@CLASS+'','')+a2 FROM a WHERE a1=@a1 order by a1 RETURN @CLASS END select a1,dbo.get_string(a1)as a2 from [A] group by a1 ----------------结果---------------------------- /* a1 a2 ----------- -------------------------------------------------- 1 ab 2 xyz(所影响的行数为 2 行) */
2000只能用函数,2005还可以用CTE和XML,代码见楼上
--> 测试数据:[tb] if object_id('[tb]') is not null drop table [tb] go create table [tb]([id] int,[value] varchar(10)) insert [tb] select 1,'a' union all select 1,'b' union all select 2,'x' union all select 2,'y' union all select 2,'z' --------------开始查询-------------------------- ;with cte as (select id,value from tb union all select a.id,cast(b.value +a.value as varchar(10)) from cte a,tb b where a.id = b.id and left(a.value,1)>b.value) select id,max(right(' '+value,6)) as value from cte group by id id value ----------- ------------ 1 ab 2 xyz(2 行受影响)
RETURNS VARCHAR(50)
AS
BEGIN
DECLARE @CLASS VARCHAR(50)
SELECT @CLASS=ISNULL(@CLASS+' ','')+res FROM tB WHERE name=@name order by name
RETURN @CLASS
END
标题:按某字段合并字符串之一(简单合并)
作者:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)
时间:2008-11-06
地点:广东深圳描述:将如下形式的数据按id字段合并value字段。
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
需要得到结果:
id value
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加)
*/
--1、sql2000中只能用自定义的函数解决
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
gocreate function dbo.f_str(@id int) returns varchar(100)
as
begin
declare @str varchar(1000)
set @str = ''
select @str = @str + ',' + cast(value as varchar) from tb where id = @id
set @str = right(@str , len(@str) - 1)
return @str
end
go--调用函数
select id , value = dbo.f_str(id) from tb group by iddrop function dbo.f_str
drop table tb
--2、sql2005中的方法
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
goselect id, [value] = stuff((select ',' + [value] from tb t where id = tb.id for xml path('')) , 1 , 1 , '')
from tb
group by iddrop table tb
--3、使用游标合并数据
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
declare @t table(id int,value varchar(100))--定义结果集表变量
--定义游标并进行合并处理
declare my_cursor cursor local for
select id , value from tb
declare @id_old int , @id int , @value varchar(10) , @s varchar(100)
open my_cursor
fetch my_cursor into @id , @value
select @id_old = @id , @s=''
while @@FETCH_STATUS = 0
begin
if @id = @id_old
select @s = @s + ',' + cast(@value as varchar)
else
begin
insert @t values(@id_old , stuff(@s,1,1,''))
select @s = ',' + cast(@value as varchar) , @id_old = @id
end
fetch my_cursor into @id , @value
END
insert @t values(@id_old , stuff(@s,1,1,''))
close my_cursor
deallocate my_cursorselect * from @t
drop table tb
-- Author :fredrickhu(小F,向高手学习)
-- Date :2010-01-05 17:18:03
-- Version:
-- Microsoft SQL Server 2005 - 9.00.4035.00 (Intel X86)
-- Nov 24 2008 13:01:59
-- Copyright (c) 1988-2005 Microsoft Corporation
-- Developer Edition on Windows NT 5.1 (Build 2600: Service Pack 3)
--
----------------------------------------------------------------
--> 测试数据:[tb]
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([id] int,[value] varchar(1))
insert [tb]
select 1,'a' union all
select 1,'b' union all
select 2,'x' union all
select 2,'y' union all
select 2,'z'
--------------开始查询--------------------------
select id, [values]=(select ''+[value] from tb t where id=tb.id for xml path(''))
from tb
group by id
----------------结果----------------------------
/*id values
----------- ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
1 ab
2 xyz(2 行受影响)
*/
--*******************************************************************************************
表结构,数据如下:
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc 需要得到结果:
id values
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加) 1. 旧的解决方法(在sql server 2000中只能用函数解决。)
--=============================================================================
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
--1. 创建处理函数
CREATE FUNCTION dbo.f_strUnite(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ''
SELECT @str = @str + ',' + value FROM tb WHERE id=@id
RETURN STUFF(@str, 1, 1, '')
END
GO
-- 调用函数
SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id
drop table tb
drop function dbo.f_strUnite
go
/*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(所影响的行数为 2 行)
*/
--===================================================================================
2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。)
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
-- 查询处理
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), ' <N value="', ','), '"/>', ''), 1, 1, '')
)N
drop table tb /*
id values
----------- -----------
1 aa,bb
2 aaa,bbb,ccc (2 行受影响)
*/ --SQL2005中的方法2
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '')
from tb
group by id /*
id values
----------- --------------------
1 aa,bb
2 aaa,bbb,ccc (2 row(s) affected) */ drop table tb
create table tb (a1 int, a2 varchar(10))
insert into tb values(1 ,'a')
insert into tb values(1 ,'b')
insert into tb values(2 ,'x')
insert into tb values(2 ,'y')
insert into tb values(2 ,'z')
go
create function dbo.f_str(@a1 int) returns varchar(100)
as
begin
declare @str varchar(1000)
set @str = ''
select @str = @str + cast(a2 as varchar) from tb where a1 = @a1
return @str
end
go--调用函数
select a1 , a2 = dbo.f_str(a1) from tb group by a1drop function dbo.f_str
drop table tb /*
a1 a2
----------- ----------------------------------------------------------------------------------------------------
1 ab
2 xyz(所影响的行数为 2 行)*/
-- Author :SQL77(只为思齐老)
-- Date :2010-01-05 17:19:25
-- Version:
-- Microsoft SQL Server 2000 - 8.00.194 (Intel X86)
-- Aug 6 2000 00:57:48
-- Copyright (c) 1988-2000 Microsoft Corporation
-- Desktop Engine on Windows NT 5.1 (Build 2600: Service Pack 3)
--
----------------------------------------------------------------
--> 测试数据:[A]
if object_id('[A]') is not null drop table [A]
go
create table [A]([a1] int,[a2] varchar(1))
insert [A]
select 1,'a' union all
select 1,'b' union all
select 2,'x' union all
select 2,'y' union all
select 2,'z'
--------------开始查询--------------------------
alter FUNCTION GET_STRING(@a1 int)
RETURNS VARCHAR(50)
AS
BEGIN
DECLARE @CLASS VARCHAR(50)
SELECT @CLASS=ISNULL(@CLASS+'','')+a2 FROM a WHERE a1=@a1 order by a1
RETURN @CLASS
END
select a1,dbo.get_string(a1)as a2 from [A] group by a1
----------------结果----------------------------
/*
a1 a2
----------- --------------------------------------------------
1 ab
2 xyz(所影响的行数为 2 行)
*/
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([id] int,[value] varchar(10))
insert [tb]
select 1,'a' union all
select 1,'b' union all
select 2,'x' union all
select 2,'y' union all
select 2,'z'
--------------开始查询--------------------------
;with cte
as
(select id,value from tb
union all
select a.id,cast(b.value +a.value as varchar(10))
from cte a,tb b where a.id = b.id and left(a.value,1)>b.value)
select id,max(right(' '+value,6)) as value
from cte
group by id
id value
----------- ------------
1 ab
2 xyz(2 行受影响)