需要把一个字符串拆分后重新拼接。从网上找了段拆分的,但是不知该怎么拼接了。各位大侠帮帮忙declare @strSplitString nvarchar(1000)--要拆分的字符串
declare @strSplit nvarchar(10)-- 分隔符,如:逗号
set @strSplitString = ',336,22,11,14,16,17,21,12,32,'
set @strSplit = ','
declare @finalValue nvarchar(1000)
declare @location int
declare @strat int
declare @resultString nvarchar(100) --存储拆分后的字符SET @strSplitString = @strSplit + @strSplitString + @strSplitSet @location = CHARINDEX(@strSplit,@strSplitString)BEGIN TRAN --开始事务处理
WHILE @location <> 0
BEGIN
SET @strat = @location
SET @location = CHARINDEX(@strSplit,@strSplitString,@strat+1)
IF @location > 0
BEGIN
SET @resultString = '1_'+subString(@strSplitString,@strat+1,@location-@strat-1)+','--拆分后的字符 print @resultString
END
END
declare @strSplit nvarchar(10)-- 分隔符,如:逗号
set @strSplitString = ',336,22,11,14,16,17,21,12,32,'
set @strSplit = ','
declare @finalValue nvarchar(1000)
declare @location int
declare @strat int
declare @resultString nvarchar(100) --存储拆分后的字符SET @strSplitString = @strSplit + @strSplitString + @strSplitSet @location = CHARINDEX(@strSplit,@strSplitString)BEGIN TRAN --开始事务处理
WHILE @location <> 0
BEGIN
SET @strat = @location
SET @location = CHARINDEX(@strSplit,@strSplitString,@strat+1)
IF @location > 0
BEGIN
SET @resultString = '1_'+subString(@strSplitString,@strat+1,@location-@strat-1)+','--拆分后的字符 print @resultString
END
END
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
欲按id,分拆value列, 分拆后结果如下:
id value
----------- --------
1 aa
1 bb
2 aaa
2 bbb
2 ccc 1. 旧的解决方法(sql server 2000)
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.id, SUBSTRING(A.[values], B.id, CHARINDEX(',', A.[values] + ',', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING(',' + A.[values], B.id, 1) = ',' DROP TABLE # 2. 新的解决方法(sql server 2005) create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go
SELECT A.id, B.value
FROM(
SELECT id, [value] = CONVERT(xml,' <root> <v>' + REPLACE([value], ',', ' </v> <v>') + ' </v> </root>') FROM tb
)A
OUTER APPLY(
SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
)B DROP TABLE tb /*
id value
----------- ------------------------------
1 aa
1 bb
2 aaa
2 bbb
2 ccc (5 行受影响)
*/
--*******************************************************************************************
表结构,数据如下:
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc 需要得到结果:
id values
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加) 1. 旧的解决方法(在sql server 2000中只能用函数解决。)
--=============================================================================
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
--1. 创建处理函数
CREATE FUNCTION dbo.f_strUnite(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ''
SELECT @str = @str + ',' + value FROM tb WHERE id=@id group by value
RETURN STUFF(@str, 1, 1, '')
END
GO
-- 调用函数
SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id
drop table tb
drop function dbo.f_strUnite
go
/*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(所影响的行数为 2 行)
*/
--===================================================================================
2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。)
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
-- 查询处理
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), ' <N value="', ','), '"/>', ''), 1, 1, '')
)N
drop table tb /*
id values
----------- -----------
1 aa,bb
2 aaa,bbb,ccc (2 行受影响)
*/ --SQL2005中的方法2
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '')
from tb
group by id /*
id values
----------- --------------------
1 aa,bb
2 aaa,bbb,ccc (2 row(s) affected) */ drop table tb
不知道我说明白没
declare @strSplitString nvarchar(1000)--要拆分的字符串
declare @strSplit nvarchar(10)-- 分隔符,如:逗号
set @strSplitString = ',336,22,11,14,16,17,21,12,32,'
set @strSplit = ','
declare @finalValue nvarchar(1000)
declare @location int
declare @strat int
declare @resultString nvarchar(100) --存储拆分后的字符
declare @ret nvarchar(100)
--SET @strSplitString = @strSplit + @strSplitString + @strSplit Set @location = CHARINDEX(@strSplit,@strSplitString)
set @resultString = ''WHILE @location <> 0
BEGIN
SET @strat = @location
SET @location = CHARINDEX(@strSplit,@strSplitString,@strat+1)
IF @location > 0
BEGIN
SET @ret = '1_'+subString(@strSplitString,@strat+1,@location-@strat-1)+','--拆分后的字符 select @resultString = @resultString + @ret
END
ENDselect substring(@resultString,1,len(@resultString) - 1)
--结果
--------------------
1_336,1_22,1_11,1_14,1_16,1_17,1_21,1_12,1_32
declare @str nvarchar(30) --加入的字符
declare @strSplitString nvarchar(1000)--要拆分的字符串
select @str = '1_',
@strSplitString = ',336,22,11,14,16,17,21,12,32,'select substring(replace(@strSplitString,',',','+@str),2,len(replace(@strSplitString,',',','+@str)) - 4)
--结果
-----------------------
1_336,1_22,1_11,1_14,1_16,1_17,1_21,1_12,1_32
create function myfun
(
@str varchar(max), --要拆分的字符串
@sep varchar(1)--分隔符
)
returns varchar(max)
as
begin
declare @index int
declare @ss varchar(max)
set @index=0
set @ss='';
select @index=charindex(@sep,@str)
while(@index<>0)
begin
select @ss=@ss+'@ss'+substring(@str,1,@index-1)+',';
set @str=stuff(@str,1,@index,'')
select @index=charindex(@sep,@str)
end
set @ss=@ss+'@ss'+@str
return @ss
end