表结构如下:Times Warehouse CostCenter
4 4001 180KNC04
16 4001 180TCL03
31 4001 180YZJ03
12 4003 180BUL01
323 4003 180MET01
716 4005 180BUL01
8 4006 180WGE02
8 4007 180WKS02 Times表示重复次数,希望得到每一个Warehouse和CostCenter对应次数最多的纪录,结果如下:Times Warehouse CostCenter
31 4001 180YZJ03
323 4003 180MET01
716 4005 180BUL01
8 4006 180WGE02
8 4007 180WKS02 请大家指教!
4 4001 180KNC04
16 4001 180TCL03
31 4001 180YZJ03
12 4003 180BUL01
323 4003 180MET01
716 4005 180BUL01
8 4006 180WGE02
8 4007 180WKS02 Times表示重复次数,希望得到每一个Warehouse和CostCenter对应次数最多的纪录,结果如下:Times Warehouse CostCenter
31 4001 180YZJ03
323 4003 180MET01
716 4005 180BUL01
8 4006 180WGE02
8 4007 180WKS02 请大家指教!
max(Times) as Times,
Warehouse,
CostCenter
from
tb
group by
Warehouse,
CostCenter
Warehouse,
CostCenter ,
max(Times) as Times
from
tb
group by
Warehouse,
CostCenter
*
from
tb t
where
not exists(select 1 from tb where Warehouse=t.Warehouse and CostCenter=t.CostCenter and Times>t.Times)
from tb
group by Warehouse,CostCenter
order by Warehouse,CostCenter
not exists(select 1 from tb where Warehouse=t.Warehouse and Times>t.Times)
/******************************************************************************************************************************************************
1、Num、Name相同的重复值记录,没有大小关系只保留一条
2、Name相同,ID有大小关系时,保留大或小其中一个记录
整理人:中国风(Roy)日期:2008.06.06
******************************************************************************************************************************************************/--1、用于查询重复处理记录(如果列没有大小关系时2000用生成自增列和临时表处理,SQL2005用row_number函数处理)--> --> (Roy)生成測試數據
if not object_id('Tempdb..#T') is null
drop table #T
Go
Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2))
Insert #T
select 1,N'A',N'A1' union all
select 2,N'A',N'A2' union all
select 3,N'A',N'A3' union all
select 4,N'B',N'B1' union all
select 5,N'B',N'B2'
Go
--I、Name相同ID最小的记录(推荐用1,2,3),方法3在SQl05时,效率高于1、2
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID<a.ID)方法2:
select a.* from #T a join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID方法3:
select * from #T a where ID=(select min(ID) from #T where Name=a.Name)方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID>=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 方法5:
select * from #T a group by ID,Name,Memo having ID=(select min(ID)from #T where Name=a.Name)方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)=0方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID)方法8:
select * from #T a where ID!>all(select ID from #T where Name=a.Name)方法9(注:ID为唯一时可用):
select * from #T a where ID in(select min(ID) from #T group by Name)--SQL2005:方法10:
select ID,Name,Memo from (select *,min(ID)over(partition by Name) as MinID from #T a)T where ID=MinID方法11:select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID) as MinID from #T a)T where MinID=1生成结果:
/*
ID Name Memo
----------- ---- ----
1 A A1
4 B B1(2 行受影响)
*/
--II、Name相同ID最大的记录,与min相反:
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID>a.ID)方法2:
select a.* from #T a join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID order by ID方法3:
select * from #T a where ID=(select max(ID) from #T where Name=a.Name) order by ID方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID<=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 方法5:
select * from #T a group by ID,Name,Memo having ID=(select max(ID)from #T where Name=a.Name)方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)=0方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID desc)方法8:
select * from #T a where ID!<all(select ID from #T where Name=a.Name)方法9(注:ID为唯一时可用):
select * from #T a where ID in(select max(ID) from #T group by Name)--SQL2005:方法10:
select ID,Name,Memo from (select *,max(ID)over(partition by Name) as MinID from #T a)T where ID=MinID方法11:
select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID desc) as MinID from #T a)T where MinID=1生成结果2:
/*
ID Name Memo
----------- ---- ----
3 A A3
5 B B2(2 行受影响)
*/
SELECT Warehouse ,MAX(NUM) ,CostCenter FROM
(SELECT Warehouse ,CostCenter ,COUNT(CostCenter )NUM FROM TB GROUP BY Warehouse )) AS T1
ON T.CostCenter =T1.CostCenter AND T.Warehouse =T1.Warehouse
from tb
group by Warehouse,CostCenter
(SELECT Warehouse ,CostCenter FROM TB
WHERE CostCenter IN
(SELECT MAX(NUM) FROM (SELECT Warehouse ,CostCenter ,COUNT(CostCenter )NUM FROM TB GROUP BY Warehouse )AS T1 GROUP BY CostCenter ))
AS T1
ON T.CostCenter =T1.CostCenter AND T.Warehouse =T1.Warehouse
not exists(select 1 from tb where Warehouse=t.Warehouse and Times>t.Times)这个结果是对的!
谢谢大家的帮助,特别感谢wufeng4552!另外能否简单解释下, 有点看不懂太懂。