create function f_strc(@name varchar(10)) returns varchar(100) as begin declare @s varchar(100) select @s = isnull(@s+',','')+name from ta where name = @name return @s end go select name,dbo.f_strc(name) from ta group by name
-------------------------------------------> 测试时间:2009-07-27 --> 我的淘宝:http://shop36766744.taobao.com/--------------------------------------------------if object_id('[TB]') is not null drop table [TB] create table [TB]([id] int,[name] varchar(4),[orgin] varchar(4)) insert [TB] select 1,'liu','广东' union all select 2,'liu','广州' union all select 3,'ling','海南' union all select 4,'ling','海口'select * from [TB]create function dbo.f_str(@name varchar(10)) returns varchar(100) as begin declare @str varchar(1000) select @str = isnull(@str + ',' ,'')+ orgin from tb where name = @name return @str end go select name,dbo.f_str(name) from TB group by name,id/* name ---- ---------------------------------------------------------------------------------------------------- ling 海南,海口 ling 海南,海口 liu 广东,广州 liu 广东,广州(所影响的行数为 4 行) */ drop table TB drop function dbo.f_str
合并列值 原著:邹建 改编:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开) 2007-12-16 广东深圳 表结构,数据如下: id value ----- ------ 1 aa 1 bb 2 aaa 2 bbb 2 ccc 需要得到结果: id values ------ ----------- 1 aa,bb 2 aaa,bbb,ccc 即:group by id, 求 value 的和(字符串相加) 1. 旧的解决方法(在sql server 2000中只能用函数解决。) --1. 创建处理函数 create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go CREATE FUNCTION dbo.f_str(@id int) RETURNS varchar(8000) AS BEGIN DECLARE @r varchar(8000) SET @r = '' SELECT @r = @r + ',' + value FROM tb WHERE id=@id RETURN STUFF(@r, 1, 1, '') END GO -- 调用函数 SELECt id, value = dbo.f_str(id) FROM tb GROUP BY id drop table tb drop function dbo.f_str /* id value ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc (所影响的行数为 2 行) */ --2、另外一种函数. create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go --创建一个合并的函数 create function f_hb(@id int) returns varchar(8000) as begin declare @str varchar(8000) set @str = '' select @str = @str + ',' + cast(value as varchar) from tb where id = @id set @str = right(@str , len(@str) - 1) return(@str) End go --调用自定义函数得到结果: select distinct id ,dbo.f_hb(id) as value from tb drop table tb drop function dbo.f_hb /* id value ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc (所影响的行数为 2 行) */ 2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。) create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go -- 查询处理 SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY( SELECT [values]= STUFF(REPLACE(REPLACE( ( SELECT value FROM tb N WHERE id = A.id FOR XML AUTO ), ' <N value="', ','), '"/>', ''), 1, 1, '') )N drop table tb /* id values ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc (2 行受影响) */ --SQL2005中的方法2 create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '') from tb group by id /* id values ----------- -------------------- 1 aa,bb 2 aaa,bbb,ccc (2 row(s) affected) */ drop table tb
returns varchar(100)
as
begin
declare @s varchar(100)
select @s = isnull(@s+',','')+name from ta where name = @name
return @s
end
go
select name,dbo.f_strc(name) from
ta group by name
-------------------------------------------> 测试时间:2009-07-27
--> 我的淘宝:http://shop36766744.taobao.com/--------------------------------------------------if object_id('[TB]') is not null drop table [TB]
create table [TB]([id] int,[name] varchar(4),[orgin] varchar(4))
insert [TB]
select 1,'liu','广东' union all
select 2,'liu','广州' union all
select 3,'ling','海南' union all
select 4,'ling','海口'select * from [TB]create function dbo.f_str(@name varchar(10)) returns varchar(100)
as
begin
declare @str varchar(1000)
select @str = isnull(@str + ',' ,'')+ orgin from tb where name = @name
return @str
end
go
select name,dbo.f_str(name) from TB group by name,id/*
name
---- ----------------------------------------------------------------------------------------------------
ling 海南,海口
ling 海南,海口
liu 广东,广州
liu 广东,广州(所影响的行数为 4 行)
*/
drop table TB
drop function dbo.f_str
http://topic.csdn.net/u/20080612/22/c850499f-bce3-4877-82d5-af2357857872.html?90428
原著:邹建
改编:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开) 2007-12-16 广东深圳 表结构,数据如下:
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc 需要得到结果:
id values
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加) 1. 旧的解决方法(在sql server 2000中只能用函数解决。)
--1. 创建处理函数
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go CREATE FUNCTION dbo.f_str(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @r varchar(8000)
SET @r = ''
SELECT @r = @r + ',' + value FROM tb WHERE id=@id
RETURN STUFF(@r, 1, 1, '')
END
GO -- 调用函数
SELECt id, value = dbo.f_str(id) FROM tb GROUP BY id drop table tb
drop function dbo.f_str /*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(所影响的行数为 2 行)
*/ --2、另外一种函数.
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go --创建一个合并的函数
create function f_hb(@id int)
returns varchar(8000)
as
begin
declare @str varchar(8000)
set @str = ''
select @str = @str + ',' + cast(value as varchar) from tb where id = @id
set @str = right(@str , len(@str) - 1)
return(@str)
End
go --调用自定义函数得到结果:
select distinct id ,dbo.f_hb(id) as value from tb drop table tb
drop function dbo.f_hb /*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(所影响的行数为 2 行)
*/ 2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。)
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
-- 查询处理
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), ' <N value="', ','), '"/>', ''), 1, 1, '')
)N
drop table tb /*
id values
----------- -----------
1 aa,bb
2 aaa,bbb,ccc (2 行受影响)
*/ --SQL2005中的方法2
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '')
from tb
group by id /*
id values
----------- --------------------
1 aa,bb
2 aaa,bbb,ccc (2 row(s) affected) */ drop table tb