表数据 job operation
11212 1
11212 2
11212 3
select JobNo from table as sh where exists(select JobNo from table
where JobNo=sh.JobNo and Operation<sh.Operation) 用这个语句 如果同一个Job 有两行数据 那么取出的是工序小的行可问题: 如果有三行或者三行以上的数据 我怎么取工序最小的行
11212 1
11212 2
11212 3
select JobNo from table as sh where exists(select JobNo from table
where JobNo=sh.JobNo and Operation<sh.Operation) 用这个语句 如果同一个Job 有两行数据 那么取出的是工序小的行可问题: 如果有三行或者三行以上的数据 我怎么取工序最小的行
where JobNo=sh.JobNo and Operation <sh.Operation)
where JobNo=sh.JobNo and Operation <sh.Operation)
where JobNo=sh.JobNo and Operation <sh.Operation)
/******************************************************************************************************************************************************
1、Num、Name相同的重复值记录,没有大小关系只保留一条
2、Name相同,ID有大小关系时,保留大或小其中一个记录
整理人:中国风(Roy)日期:2008.06.06
******************************************************************************************************************************************************/--1、用于查询重复处理记录(如果列没有大小关系时2000用生成自增列和临时表处理,SQL2005用row_number函数处理)--> --> (Roy)生成測試數據
if not object_id('Tempdb..#T') is null
drop table #T
Go
Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2))
Insert #T
select 1,N'A',N'A1' union all
select 2,N'A',N'A2' union all
select 3,N'A',N'A3' union all
select 4,N'B',N'B1' union all
select 5,N'B',N'B2'
Go
--I、Name相同ID最小的记录(推荐用1,2,3),方法3在SQl05时,效率高于1、2
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID<a.ID)方法2:
select a.* from #T a join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID方法3:
select * from #T a where ID=(select min(ID) from #T where Name=a.Name)方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID>=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 方法5:
select * from #T a group by ID,Name,Memo having ID=(select min(ID)from #T where Name=a.Name)方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)=0方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID)方法8:
select * from #T a where ID!>all(select ID from #T where Name=a.Name)方法9(注:ID为唯一时可用):
select * from #T a where ID in(select min(ID) from #T group by Name)--SQL2005:方法10:
select ID,Name,Memo from (select *,min(ID)over(partition by Name) as MinID from #T a)T where ID=MinID方法11:select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID) as MinID from #T a)T where MinID=1生成结果:
/*
ID Name Memo
----------- ---- ----
1 A A1
4 B B1(2 行受影响)
*/
不好意思 是我发错了 我原句有 not 这个我的问题 这个句子 会把工序 1和3的都取出来 因为 1比3小 3比5小
INSERT TBTEST
SELECT 11212, 1 UNION ALL
SELECT 11212, 2 UNION ALL
SELECT 11212, 3 UNION ALL
SELECT 11212, 5 SELECT * FROM TBTEST T WHERE NOT EXISTS(SELECT 1 FROM TBTEST WHERE JOB=T.JOB AND T.operation>operation)
job operation
----------- -----------
11212 1(所影响的行数为 1 行)
where JobNo=sh.JobNo and Operation <sh.Operation)
if object_id('[ta]') is not null drop table [ta]
create table ta(job char(4),id int)
insert ta
select 'aa', 1 union all
select 'aa', 2 union all
select 'aa', 3 union all
select 'bb', 1 union all
select 'bb', 2 union all
select 'bb', 3
go
select * from ta #T where not exists(select 1 from ta where job=#T.job and id<#T.id)aa 1
bb 1
INSERT [table]
SELECT 11212, 1 UNION ALL
SELECT 11212, 2 UNION ALL
SELECT 11212, 3 UNION ALL
SELECT 11212, 5 select JobNo,operation from [table] as sh where Operation=(select min(Operation) from [Table] group by JobNo )/*--------------------------
11212 1------------------------*/
INSERT [table]
SELECT 11212, 1 UNION ALL
SELECT 11212, 2 UNION ALL
SELECT 11212, 3 UNION ALL
SELECT 11212, 5 select JobNo,operation from [table] as sh where Operation=(select min(Operation) from [Table] group by JobNo ) /*--------------------------
11212 1 ------------------------*/
JobNo
from
[table] as sh
where
not exists
(select JobNo
from table
where JobNo=sh.JobNo and Operation <sh.Operation
)
意思是,在表中不存在比sh里Operation小的数据。