用这个sql
SELECT JH5KSCD,JH5SQNO,jh5hono
FROM SADT_WK_JH5,sadt_wk_jh1
where JH5MJCD = :P_MJCD
and jh5kscd = jh1kscd
ORDER BY JH5KSCD,JH5SQNO
查询出来的结果为
jh5kscd jh5sqno jh5hono
277000 1 271403
277000 1 271403
277000 2 272021
277000 2 272021
277000 3 271403
277000 3 271403
我想要的结果是每次的结果只出来一次
这个表的sql的语句该是怎么样的
SELECT JH5KSCD,JH5SQNO,jh5hono
FROM SADT_WK_JH5,sadt_wk_jh1
where JH5MJCD = :P_MJCD
and jh5kscd = jh1kscd
ORDER BY JH5KSCD,JH5SQNO
查询出来的结果为
jh5kscd jh5sqno jh5hono
277000 1 271403
277000 1 271403
277000 2 272021
277000 2 272021
277000 3 271403
277000 3 271403
我想要的结果是每次的结果只出来一次
这个表的sql的语句该是怎么样的
FROM SADT_WK_JH5,sadt_wk_jh1
where JH5MJCD = :P_MJCD
and jh5kscd = jh1kscd
ORDER BY JH5KSCD,JH5SQNO
SELECT distinct JH5KSCD,JH5SQNO,jh5hono
FROM SADT_WK_JH5,sadt_wk_jh1
where JH5MJCD = :P_MJCD
and jh5kscd = jh1kscd
ORDER BY JH5KSCD,JH5SQNO
declare c cursor for
SELECT JH5KSCD,JH5SQNO,jh5hono
FROM SADT_WK_JH5,sadt_wk_jh1
where JH5MJCD = [:P_MJCD]
and jh5kscd = jh1kscd
ORDER BY JH5KSCD,JH5SQNO
open c
fetch next from c --每查询一次按一次--查询完毕的时候再删除游标
close c
deallocate c
FROM SADT_WK_JH5,sadt_wk_jh1
where JH5MJCD = :P_MJCD
and jh5kscd = jh1kscd
GROUP BY JH5KSCD,JH5SQNO,jh5hono
ORDER BY JH5KSCD,JH5SQNO
distinct
JH3TKCD,
JH3KSCD,
JH3SJTN,
JH3KKCD,
JH3HIKJ,
JH3HIKN,
JH3HONO,
JH3HINO,
SUBSTRB(JPDATE(JH1LTDT),1,12)||'分' AS SUBSTRB_JPDATE_JH1LTDT_1_12,
(JH1KSCD) AS KSCD_BASE,
KSJKSKJ,KSJTEL1,KSJFAX,KSJKSCD,
DECODE(RTRIM(JH3GYKG),'11','経過的要介護','12','要支援1','13','要支援2','21','要介護1','22','要介護2','23','要介護3','24','要介護4','25','要介護5','未定') AS JH3GYKG,
JPDATE(JH3WADT) AS JH3WADT,
DECODE(JH3NTKB,'0','認定済','1','申請中','2','更新中','9','認定無',' ') AS JH3NTKB,
JH3CUNT,SUBSTR(JPDATE(JH3JHDT),1,8) AS JH3JHDT,
JH5SQNO,JH5KSCDFROM SADT_WK_JH1 t,SADT_WK_JH2,SADT_WK_JH3,SADT_TM_KSJ,SADT_WK_JH5
where JH2mjcd = JH3mjcd
and JH1MJCD=$P{P_MJCD}
AND JH1KSCD = KSJKSCD
AND JH3mjcd = JH1MJCD
and jh3kscd = jh1kscd
and JH5MJCD=$P{P_MJCD}
and jh5sqno = jh2dgno
ORDER BY JH3KSCD,SASY_TO_M_KANA(JH3SJTN) ,SASY_TO_M_KANA(JH3HIKN),JH5KSCD,JH5SQNO
但是在这个语句里面用了distinct还是不行
jh3tkcd jh3hono jh3hino jh3kkcd jh5sqno jh5kscd
10002 271403 1111000298 10002H 1 2770000
10002 271403 1111000298 10002H 2 2770000
10002 271403 1111000298 10002H 3 2770000
10002 271403 1111000298 10002H 4 2770000
10311 271403 1111111111 10001H 1 2770000
10311 271403 1111111111 10001H 2 2770000
10311 271403 1111111111 10001H 3 2770000
10311 271403 1111111111 10001H 4 2770000现在我想要的数据是
jh3tkcd jh3hono jh3hino jh3kkcd jh5sqno jh5kscd
10002 271403 1111000298 10002H 1 2770000
10311 271403 1111111111 10001H 2 2770000
jh3tkcd jh3hono jh3hino jh3kkcd jh5sqno jh5kscd
10002 271403 1111000298 10002H 1 2770000
10311 271403 1111111111 10001H 1 2770000
或:
jh3tkcd jh3hono jh3hino jh3kkcd jh5sqno jh5kscd
10002 271403 1111000298 10002H 4 2770000
10311 271403 1111111111 10001H 4 2770000 可以理解,你那个结果不好理解.
所以就在这里问了
如果我要一样的jh5sqno 的结果的话
该是怎么回事呢?
参考这个:
--按某一字段分组取最大(小)值所在行的数据
--(爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开) 2007-10-23于浙江杭州)
/*
数据如下:
name val memo
a 2 a2(a的第二个值)
a 1 a1--a的第一个值
a 3 a3:a的第三个值
b 1 b1--b的第一个值
b 3 b3:b的第三个值
b 2 b2b2b2b2
b 4 b4b4
b 5 b5b5b5b5b5
*/
--创建表并插入数据:
create table tb(name varchar(10),val int,memo varchar(20))
insert into tb values('a', 2, 'a2(a的第二个值)')
insert into tb values('a', 1, 'a1--a的第一个值')
insert into tb values('a', 3, 'a3:a的第三个值')
insert into tb values('b', 1, 'b1--b的第一个值')
insert into tb values('b', 3, 'b3:b的第三个值')
insert into tb values('b', 2, 'b2b2b2b2')
insert into tb values('b', 4, 'b4b4')
insert into tb values('b', 5, 'b5b5b5b5b5')
go--一、按name分组取val最大的值所在行的数据。
--方法1:
select a.* from tb a where val = (select max(val) from tb where name = a.name) order by a.name
--方法2:
select a.* from tb a where not exists(select 1 from tb where name = a.name and val > a.val)
--方法3:
select a.* from tb a,(select name,max(val) val from tb group by name) b where a.name = b.name and a.val = b.val order by a.name
--方法4:
select a.* from tb a inner join (select name , max(val) val from tb group by name) b on a.name = b.name and a.val = b.val order by a.name
--方法5
select a.* from tb a where 1 > (select count(*) from tb where name = a.name and val > a.val ) order by a.name
/*
name val memo
---------- ----------- --------------------
a 3 a3:a的第三个值
b 5 b5b5b5b5b5
*/--二、按name分组取val最小的值所在行的数据。
--方法1:
select a.* from tb a where val = (select min(val) from tb where name = a.name) order by a.name
--方法2:
select a.* from tb a where not exists(select 1 from tb where name = a.name and val < a.val)
--方法3:
select a.* from tb a,(select name,min(val) val from tb group by name) b where a.name = b.name and a.val = b.val order by a.name
--方法4:
select a.* from tb a inner join (select name , min(val) val from tb group by name) b on a.name = b.name and a.val = b.val order by a.name
--方法5
select a.* from tb a where 1 > (select count(*) from tb where name = a.name and val < a.val) order by a.name
/*
name val memo
---------- ----------- --------------------
a 1 a1--a的第一个值
b 1 b1--b的第一个值
*/--三、按name分组取第一次出现的行所在的数据。
select a.* from tb a where val = (select top 1 val from tb where name = a.name) order by a.name
/*
name val memo
---------- ----------- --------------------
a 2 a2(a的第二个值)
b 1 b1--b的第一个值
*/--四、按name分组随机取一条数据。
select a.* from tb a where val = (select top 1 val from tb where name = a.name order by newid()) order by a.name
/*
name val memo
---------- ----------- --------------------
a 1 a1--a的第一个值
b 5 b5b5b5b5b5
*/--五、按name分组取最小的两个(N个)val
select a.* from tb a where 2 > (select count(*) from tb where name = a.name and val < a.val ) order by a.name,a.val
select a.* from tb a where val in (select top 2 val from tb where name=a.name order by val) order by a.name,a.val
select a.* from tb a where exists (select count(*) from tb where name = a.name and val < a.val having Count(*) < 2) order by a.name,a.val
/*
name val memo
---------- ----------- --------------------
a 1 a1--a的第一个值
a 2 a2(a的第二个值)
b 1 b1--b的第一个值
b 2 b2b2b2b2
*/--六、按name分组取最大的两个(N个)val
select a.* from tb a where 2 > (select count(*) from tb where name = a.name and val > a.val ) order by a.name,a.val
select a.* from tb a where val in (select top 2 val from tb where name=a.name order by val desc) order by a.name,a.val
select a.* from tb a where exists (select count(*) from tb where name = a.name and val > a.val having Count(*) < 2) order by a.name , a.val
/*
name val memo
---------- ----------- --------------------
a 2 a2(a的第二个值)
a 3 a3:a的第三个值
b 4 b4b4
b 5 b5b5b5b5b5
*/
--七,如果整行数据有重复,所有的列都相同。
/*
数据如下:
name val memo
a 2 a2(a的第二个值)
a 1 a1--a的第一个值
a 1 a1--a的第一个值
a 3 a3:a的第三个值
a 3 a3:a的第三个值
b 1 b1--b的第一个值
b 3 b3:b的第三个值
b 2 b2b2b2b2
b 4 b4b4
b 5 b5b5b5b5b5
*/
--在sql server 2000中只能用一个临时表来解决,生成一个自增列,先对val取最大或最小,然后再通过自增列来取数据。
--创建表并插入数据:
create table tb(name varchar(10),val int,memo varchar(20))
insert into tb values('a', 2, 'a2(a的第二个值)')
insert into tb values('a', 1, 'a1--a的第一个值')
insert into tb values('a', 1, 'a1--a的第一个值')
insert into tb values('a', 3, 'a3:a的第三个值')
insert into tb values('a', 3, 'a3:a的第三个值')
insert into tb values('b', 1, 'b1--b的第一个值')
insert into tb values('b', 3, 'b3:b的第三个值')
insert into tb values('b', 2, 'b2b2b2b2')
insert into tb values('b', 4, 'b4b4')
insert into tb values('b', 5, 'b5b5b5b5b5')
goselect * , px = identity(int,1,1) into tmp from tbselect m.name,m.val,m.memo from
(
select t.* from tmp t where val = (select min(val) from tmp where name = t.name)
) m where px = (select min(px) from
(
select t.* from tmp t where val = (select min(val) from tmp where name = t.name)
) n where n.name = m.name)drop table tb,tmp/*
name val memo
---------- ----------- --------------------
a 1 a1--a的第一个值
b 1 b1--b的第一个值(2 行受影响)
*/
--在sql server 2005中可以使用row_number函数,不需要使用临时表。
--创建表并插入数据:
create table tb(name varchar(10),val int,memo varchar(20))
insert into tb values('a', 2, 'a2(a的第二个值)')
insert into tb values('a', 1, 'a1--a的第一个值')
insert into tb values('a', 1, 'a1--a的第一个值')
insert into tb values('a', 3, 'a3:a的第三个值')
insert into tb values('a', 3, 'a3:a的第三个值')
insert into tb values('b', 1, 'b1--b的第一个值')
insert into tb values('b', 3, 'b3:b的第三个值')
insert into tb values('b', 2, 'b2b2b2b2')
insert into tb values('b', 4, 'b4b4')
insert into tb values('b', 5, 'b5b5b5b5b5')
goselect m.name,m.val,m.memo from
(
select * , px = row_number() over(order by name , val) from tb
) m where px = (select min(px) from
(
select * , px = row_number() over(order by name , val) from tb
) n where n.name = m.name)drop table tb/*
name val memo
---------- ----------- --------------------
a 1 a1--a的第一个值
b 1 b1--b的第一个值(2 行受影响)
*/
from table
group by jh3tkcd,jh3hono,jh3hino,jh3kkcd,jh5kscd
select jh3tkcd,jh3hono,jh3hino,jh3kkcd,identity( int, 1, 1 ) as jh5sqno,jh5kscd
from table
group by jh3tkcd,jh3hono,jh3hino,jh3kkcd,jh5kscd