比如一个表有一个字段 content 里面有两条数据         content字段第一行  a1,a2,a3,a4
第一行  b1,b2,b3,b4如何写select 把content 字段分成 4段字段1  字段2   字段3   字段4  content
a1     a2     a3      a4    a1,a2,a3,a4
b1     b2     b3      b4    b1,b2,b3,b4高手帮忙 !!!

解决方案 »

  1.   

    ----參考
    --合并分拆表
    /******************************************************************************************************************************************************
    合并分拆表数据整理人:中国风(Roy)日期:2008.06.06
    ******************************************************************************************************************************************************/--> --> (Roy)生成測試數據
     
    if not object_id('Tab') is null
        drop table Tab
    Go
    Create table Tab([Col1] int,[Col2] nvarchar(1))
    Insert Tab
    select 1,N'a' union all
    select 1,N'b' union all
    select 1,N'c' union all
    select 2,N'd' union all
    select 2,N'e' union all
    select 3,N'f'
    Go合并表:SQL2000用函数:go
    if object_id('F_Str') is not null
        drop function F_Str
    go
    create function F_Str(@Col1 int)
    returns nvarchar(100)
    as
    begin
        declare @S nvarchar(100)
        select @S=isnull(@S+',','')+Col2 from Tab where Col1=@Col1
        return @S
    end
    go
    Select distinct Col1,Col2=dbo.F_Str(Col1) from TabgoSQL2005用XML:方法1:select 
        a.Col1,Col2=stuff(b.Col2.value('/R[1]','nvarchar(max)'),1,1,'')
    from 
        (select distinct COl1 from Tab) a
    Cross apply
        (select COl2=(select N','+Col2 from Tab where Col1=a.COl1 For XML PATH(''), ROOT('R'), TYPE))b方法2:select 
        a.Col1,COl2=replace(b.Col2.value('/Tab[1]','nvarchar(max)'),char(44)+char(32),char(44))
    from 
        (select distinct COl1 from Tab) a
    cross apply
        (select Col2=(select COl2 from Tab  where COl1=a.COl1 FOR XML AUTO, TYPE)
                    .query('<Tab>
                    {for $i in /Tab[position()<last()]/@COl2 return concat(string($i),",")}
                    {concat("",string(/Tab[last()]/@COl2))}
                    </Tab>')
                    )bSQL05用CTE:;with roy as(select Col1,Col2,row=row_number()over(partition by COl1 order by COl1) from Tab)
    ,Roy2 as
    (select COl1,cast(COl2 as nvarchar(100))COl2,row from Roy where row=1 
    union all 
    select a.Col1,cast(b.COl2+','+a.COl2 as nvarchar(100)),a.row from Roy a join Roy2 b on a.COl1=b.COl1 and a.row=b.row+1)
    select Col1,Col2 from Roy2 a where row=(select max(row) from roy where Col1=a.COl1) order by Col1 option (MAXRECURSION 0)
    生成结果:
    /*
    Col1        COl2
    ----------- ------------
    1           a,b,c
    2           d,e
    3           f(3 行受影响)
    */
    拆分表:--> --> (Roy)生成測試數據
     
    if not object_id('Tab') is null
        drop table Tab
    Go
    Create table Tab([Col1] int,[COl2] nvarchar(5))
    Insert Tab
    select 1,N'a,b,c' union all
    select 2,N'd,e' union all
    select 3,N'f'
    GoSQL2000用辅助表:
    if object_id('Tempdb..#Num') is not null
        drop table #Num
    go
    select top 100 ID=Identity(int,1,1) into #Num from syscolumns a,syscolumns b
    Select 
        a.Col1,COl2=substring(a.Col2,b.ID,charindex(',',a.Col2+',',b.ID)-b.ID) 
    from 
        Tab a,#Num b
    where
        charindex(',',','+a.Col2,b.ID)=b.ID --也可用 substring(','+a.COl2,b.ID,1)=','
    SQL2005用Xml:select 
        a.COl1,b.Col2
    from 
        (select Col1,COl2=convert(xml,'<root><v>'+replace(COl2,',','</v><v>')+'</v></root>') from Tab)a
    outer apply
        (select Col2=C.v.value('.','nvarchar(100)') from a.COl2.nodes('/root/v')C(v))b
    SQL05用CTE:;with roy as 
    (select Col1,COl2=cast(left(Col2,charindex(',',Col2+',')-1) as nvarchar(100)),Split=cast(stuff(COl2+',',1,charindex(',',Col2+','),'') as nvarchar(100)) from Tab
    union all
    select Col1,COl2=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from Roy where split>''
    )
    select COl1,COl2 from roy order by COl1 option (MAXRECURSION 0)生成结果:
    /*
    Col1        COl2
    ----------- -----
    1           a
    1           b
    1           c
    2           d
    2           e
    3           f
    */
      

  2.   

    每行就三个逗号吗?用parsename()
      

  3.   

    if object_id('[tb]') is not null drop table [tb]
    go
    create table [tb]([content] varchar(11))
    insert [tb]
    select 'a1,a2,a3,a4' union all
    select 'b1,b2,b3,b4'select * from [tb]select parsename(c,4) f1,parsename(c,3) f1,parsename(c,2) f1,parsename(c,1) f1,content
    from (select content,c=replace(content,',','.') from tb) t
    --测试结果:
    /*
    f1    f2 f3 f4 content
    ---------------------
    a1 a2 a3 a4 a1,a2,a3,a4
    b1 b2 b3 b4 b1,b2,b3,b4
    */
      

  4.   

    create table tb(content varchar(20))
    insert into tb values('a1,a2,a3,a4') 
    insert into tb values('b1,b2,b3,b4')
    go
    select parsename(replace(content,',','.'),4) col1,
           parsename(replace(content,',','.'),3) col2,
           parsename(replace(content,',','.'),2) col3,
           parsename(replace(content,',','.'),1) col4,
           content
    from tb
    drop table tb /*
    col1                                                                                                                             col2                                                                                                                             col3                                                                                                                             col4                                                                                                                             content              
    -------------------------------------------------------------------------------------------------------------------------------- -------------------------------------------------------------------------------------------------------------------------------- -------------------------------------------------------------------------------------------------------------------------------- -------------------------------------------------------------------------------------------------------------------------------- -------------------- 
    a1                                                                                                                               a2                                                                                                                               a3                                                                                                                               a4                                                                                                                               a1,a2,a3,a4
    b1                                                                                                                               b2                                                                                                                               b3                                                                                                                               b4                                                                                                                               b1,b2,b3,b4(所影响的行数为 2 行)
    */
      

  5.   

    那就参考:/*
    标题:分拆列值
    作者:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)
    时间:2008-11-20
    地点:广东深圳
    描述有表tb, 如下:
    id          value
    ----------- -----------
    1           aa,bb
    2           aaa,bbb,ccc
    欲按id,分拆value列, 分拆后结果如下:
    id          value
    ----------- --------
    1           aa
    1           bb
    2           aaa
    2           bbb
    2           ccc
    */--1. 旧的解决方法(sql server 2000)
    SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.id, SUBSTRING(A.[values], B.id, CHARINDEX(',', A.[values] + ',', B.id) - B.id)
    FROM tb A, # B
    WHERE SUBSTRING(',' + A.[values], B.id, 1) = ','DROP TABLE #--2. 新的解决方法(sql server 2005) 
    create table tb(id int,value varchar(30))
    insert into tb values(1,'aa,bb')
    insert into tb values(2,'aaa,bbb,ccc')
    go
    SELECT A.id, B.value
    FROM(
        SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb
    )A
    OUTER APPLY(
        SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
    )BDROP TABLE tb/*
    id          value
    ----------- ------------------------------
    1           aa
    1           bb
    2           aaa
    2           bbb
    2           ccc(5 行受影响)
    */
      

  6.   


    select 
    字段1 =  parsename(replace([content],',','.'),4)
    字段2 =  parsename(replace([content],',','.'),3)
    字段3 =  parsename(replace([content],',','.'),2)
    字段4 =  parsename(replace([content],',','.'),1)
    [content] = content
    from tb