为什么'COPTCUDF04'=isnull((select CMSMR.MR003 from $$CMSMR AS CMSMR where CMSMR.MR002=COPMA.MA077 and CMSMR.MR001='5'),''), 这段语句不会报错
可是下面这个会提示“返回值多于一个”的错误
MOCTAUDF01=ISNULL((SELECT CMSMD.MD002 FROM $$CMSMD AS CMSMD,$$MOCTA as M WHERE M.TA021=CMSMD.MD001 AND M.TA006 LIKE '2J%'),''),
要怎么解决这个错误呢
可是下面这个会提示“返回值多于一个”的错误
MOCTAUDF01=ISNULL((SELECT CMSMD.MD002 FROM $$CMSMD AS CMSMD,$$MOCTA as M WHERE M.TA021=CMSMD.MD001 AND M.TA006 LIKE '2J%'),''),
要怎么解决这个错误呢
解决方案 »
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