如何实现取出从 M 到 N 范围内的数据?例如:
select * from News order by NewsID desc // 一共有 100 条数据我现在只需要取 从第 5 条开始到第 10 条的数据select (5到10条的数据) * from News order by NewsID desc
select * from News order by NewsID desc // 一共有 100 条数据我现在只需要取 从第 5 条开始到第 10 条的数据select (5到10条的数据) * from News order by NewsID desc
select top 6 * from News where NewsID not in(select top 5 * from News )
order by NewsID desc
select top m * from tablename where id not in (select top n id from tablename order by id asc/*|desc*/) 2.
select top m * into 临时表(或表变量) from tablename order by columnname -- 将top m笔插入到临时表
set rowcount n --只取n条结果
select * from 表变量 order by columnname desc 3.
select top n * from
(select top m * from tablename order by columnname) a
order by columnname desc
4.如果tablename里没有其他identity列,那么:
先生成一个序列,存储在一临时表中.
select identity(int) id0,* into #temp from tablename 取n到m条的语句为:
select * from #temp where id0 > =n and id0 <= m 如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行:
exec sp_dboption 你的DB名字,'select into/bulkcopy',true
5.如果表里有identity属性,那么简单:
select * from tablename where identity_col between n and m 6.SQL2005开始.可以使用row_number() over()生成行号
;with cte as
(
select id0=row_number() over(order by id),* from tablename
)
select * from cte where id0 between n to m
SQL code
select top 6 * from News where NewsID not in(select top 4 * from News )
order by NewsID desc
[/Quote]
改一下
go
with tb(id,mid,name,orde)
as
(select id,mid,name,rank() over(order by id,mid,name) as orde from t)
select * from tb where orde >=2 and orde <=3
--结果
ID MID Name
---------- ----------- --------
001 2 a
001 1 b
002 3 c
002 2 d
002 1 e
003 1 f(6 行受影响)id mid name orde
---------- ----------- ------------------
001 2 a 2
002 1 e 3(2 行受影响)========================================
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(
select 10 * from News order by NewsID desc
) t order by NewsID