table a
hth sj money
001 2008-2-1 90
003 2008-2-3 10
007 2008-2-1 90
001 2008-2-5 80
003 2008-2-9 60
005 2008-2-3 80
目的 求出某一个月的hth在时间最大的那条纪录的和
比如现在是2月.那么就是得到001在2月的最后一条纪录+003在2月的最后一条纪录+..所有的hth在2月的最后一条纪录的和值...
谢谢谢谢
hth sj money
001 2008-2-1 90
003 2008-2-3 10
007 2008-2-1 90
001 2008-2-5 80
003 2008-2-9 60
005 2008-2-3 80
目的 求出某一个月的hth在时间最大的那条纪录的和
比如现在是2月.那么就是得到001在2月的最后一条纪录+003在2月的最后一条纪录+..所有的hth在2月的最后一条纪录的和值...
谢谢谢谢
hth sj money
001 2008-2-1 90
003 2008-2-3 10
007 2008-2-1 90
001 2008-2-5 80
003 2008-2-9 60
005 2008-2-3 80 ---
select *
from tablea a
where not exists(select 1 from tablea where hth = a.hth and sj > a.sj)
-- Author: happyflsytone
-- Date:2008-10-22 22:04:38
-------------------------------------- Test Data: tablea
IF OBJECT_ID('tablea') IS NOT NULL
DROP TABLE tablea
Go
CREATE TABLE tablea(hth NVARCHAR(3),sj SMALLDATETIME,money INT)
Go
INSERT INTO tablea
SELECT '001','2008-2-1',90 UNION ALL
SELECT '003','2008-2-3',10 UNION ALL
SELECT '007','2008-2-1',90 UNION ALL
SELECT '001','2008-2-5',80 UNION ALL
SELECT '003','2008-2-9',60 UNION ALL
SELECT '005','2008-2-3',80
GO
--Start
select *
from tablea a
where not exists(select 1
from tablea
where hth = a.hth and sj > a.sj)
order by 1--Result:
/*
hth sj money
---- ----------------------- -----------
001 2008-02-05 00:00:00 80
003 2008-02-09 00:00:00 60
005 2008-02-03 00:00:00 80
007 2008-02-01 00:00:00 90(4 行受影响)*/
--End
exists是存在性的一个判断呀,查询看看当前记录是不是有同hth的SJ比自己大的记录,没有时此条满足要求所以同一个hth记录sj最大的就保留下来了
create table a(hth varchar(20),sj datetime,money numeric(18,5))
insert into a
select '001','2008-2-1','90'
union all select'003','2008-2-3','10'
union all select'007','2008-2-1','90'
union all select'001','2008-2-5','80'
union all select'003','2008-2-9','60'
union all select'005','2008-2-3','80' select sum(a.money) from(
select hth,money=max(money) from a group by hth
)a
时间自己加...
where sj=(select MAX(sj) from @T where [hth]=a.[hth])
order by [hth]
select count(*) as 记录数,sum(table11.money) as 合计 from table11, (select hth,max(sj) as sj from table11 group by hth) a
where table11.hth=a.hth and table11.sj=a.sjtable11
001 2008-02-01 00:00:00 90.0000
003 2008-02-03 00:00:00 10.0000
005 2008-02-10 00:00:00 80.0000
001 2008-02-12 00:00:00 100.0000
003 2008-02-18 00:00:00 40.0000 结果:
记录数 合计
3 220.0000
DROP TABLE tablea
Go
CREATE TABLE tablea(hth NVARCHAR(3),sj SMALLDATETIME,money INT)
Go
INSERT INTO tablea
SELECT '001','2008-2-1',90 UNION ALL
SELECT '003','2008-2-3',10 UNION ALL
SELECT '007','2008-2-1',90 UNION ALL
SELECT '001','2008-2-5',80 UNION ALL
SELECT '003','2008-2-9',60 UNION ALL
SELECT '005','2008-2-3',80
GO
select * from tablea a where sj=(select max(sj) from tablea where hth=a.hth) order by hth
/*
hth sj money
---- ------------------------------------------------------ -----------
001 2008-02-05 00:00:00 80
003 2008-02-09 00:00:00 60
005 2008-02-03 00:00:00 80
007 2008-02-01 00:00:00 90*/
DROP TABLE tablea
Go
CREATE TABLE tablea(hth NVARCHAR(3),sj SMALLDATETIME,money INT)
Go
INSERT INTO tablea
SELECT '001','2008-2-1',90 UNION ALL
SELECT '003','2008-2-3',10 UNION ALL
SELECT '007','2008-2-1',90 UNION ALL
SELECT '001','2008-2-5',80 UNION ALL
SELECT '003','2008-2-9',60 UNION ALL
SELECT '005','2008-2-3',80
GO
select * from tablea a where (select count(1) from tablea where hth=a.hth and sj>a.sj)=0/*
hth sj money
---- ------------------------------------------------------ -----------
001 2008-02-05 00:00:00 80
003 2008-02-09 00:00:00 60
005 2008-02-03 00:00:00 80
007 2008-02-01 00:00:00 90*/
/******************************************************************************************************************************************************
1、Num、Name相同的重复值记录,没有大小关系只保留一条
2、Name相同,ID有大小关系时,保留大或小其中一个记录
整理人:中国风(Roy)日期:2008.06.06
******************************************************************************************************************************************************/--1、用于查询重复处理记录(如果列没有大小关系时2000用生成自增列和临时表处理,SQL2005用row_number函数处理)--> --> (Roy)生成測試數據
if not object_id('Tempdb..#T') is null
drop table #T
Go
Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2))
Insert #T
select 1,N'A',N'A1' union all
select 2,N'A',N'A2' union all
select 3,N'A',N'A3' union all
select 4,N'B',N'B1' union all
select 5,N'B',N'B2'
Go
--I、Name相同ID最小的记录(推荐用1,2,3),方法3在SQl05时,效率高于1、2
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID<a.ID)方法2:
select a.* from #T a join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID方法3:
select * from #T a where ID=(select min(ID) from #T where Name=a.Name)方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID>=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 方法5:
select * from #T a group by ID,Name,Memo having ID=(select min(ID)from #T where Name=a.Name)方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)=0方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID)方法8:
select * from #T a where ID!>all(select ID from #T where Name=a.Name)方法9(注:ID为唯一时可用):
select * from #T a where ID in(select min(ID) from #T group by Name)--SQL2005:方法10:
select ID,Name,Memo from (select *,min(ID)over(partition by Name) as MinID from #T a)T where ID=MinID方法11:select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID) as MinID from #T a)T where MinID=1生成结果:
/*
ID Name Memo
----------- ---- ----
1 A A1
4 B B1(2 行受影响)
*/
--II、Name相同ID最大的记录,与min相反:
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID>a.ID)方法2:
select a.* from #T a join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID order by ID方法3:
select * from #T a where ID=(select max(ID) from #T where Name=a.Name) order by ID方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID<=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 方法5:
select * from #T a group by ID,Name,Memo having ID=(select max(ID)from #T where Name=a.Name)方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)=0方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID desc)方法8:
select * from #T a where ID!<all(select ID from #T where Name=a.Name)方法9(注:ID为唯一时可用):
select * from #T a where ID in(select max(ID) from #T group by Name)--SQL2005:方法10:
select ID,Name,Memo from (select *,max(ID)over(partition by Name) as MinID from #T a)T where ID=MinID方法11:
select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID desc) as MinID from #T a)T where MinID=1生成结果2:
/*
ID Name Memo
----------- ---- ----
3 A A3
5 B B2(2 行受影响)
*/--2、删除重复记录有大小关系时,保留大或小其中一个记录
--> --> (Roy)生成測試數據if not object_id('Tempdb..#T') is null
drop table #T
Go
Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2))
Insert #T
select 1,N'A',N'A1' union all
select 2,N'A',N'A2' union all
select 3,N'A',N'A3' union all
select 4,N'B',N'B1' union all
select 5,N'B',N'B2'
Go--I、Name相同ID最小的记录(推荐用1,2,3),保留最小一条
方法1:
delete a from #T a where exists(select 1 from #T where Name=a.Name and ID<a.ID)方法2:
delete a from #T a left join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID where b.Id is null方法3:
delete a from #T a where ID not in (select min(ID) from #T where Name=a.Name)方法4(注:ID为唯一时可用):
delete a from #T a where ID not in(select min(ID)from #T group by Name)方法5:
delete a from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)>0方法6:
delete a from #T a where ID<>(select top 1 ID from #T where Name=a.name order by ID)方法7:
delete a from #T a where ID>any(select ID from #T where Name=a.Name)select * from #T生成结果:
/*
ID Name Memo
----------- ---- ----
1 A A1
4 B B1(2 行受影响)
*/
--II、Name相同ID保留最大的一条记录:方法1:
delete a from #T a where exists(select 1 from #T where Name=a.Name and ID>a.ID)方法2:
delete a from #T a left join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID where b.Id is null方法3:
delete a from #T a where ID not in (select max(ID) from #T where Name=a.Name)方法4(注:ID为唯一时可用):
delete a from #T a where ID not in(select max(ID)from #T group by Name)方法5:
delete a from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)>0方法6:
delete a from #T a where ID<>(select top 1 ID from #T where Name=a.name order by ID desc)方法7:
delete a from #T a where ID<any(select ID from #T where Name=a.Name)
select * from #T
/*
ID Name Memo
----------- ---- ----
3 A A3
5 B B2(2 行受影响)
*/--3、删除重复记录没有大小关系时,处理重复值
--> --> (Roy)生成測試數據
if not object_id('Tempdb..#T') is null
drop table #T
Go
Create table #T([Num] int,[Name] nvarchar(1))
Insert #T
select 1,N'A' union all
select 1,N'A' union all
select 1,N'A' union all
select 2,N'B' union all
select 2,N'B'
Go方法1:
if object_id('Tempdb..#') is not null
drop table #
Select distinct * into # from #T--排除重复记录结果集生成临时表#truncate table #T--清空表insert #T select * from # --把临时表#插入到表#T中--查看结果
select * from #T/*
Num Name
----------- ----
1 A
2 B(2 行受影响)
*/--重新执行测试数据后用方法2
方法2:alter table #T add ID int identity--新增标识列
go
delete a from #T a where exists(select 1 from #T where Num=a.Num and Name=a.Name and ID>a.ID)--只保留一条记录
go
alter table #T drop column ID--删除标识列--查看结果
select * from #T/*
Num Name
----------- ----
1 A
2 B(2 行受影响)*/--重新执行测试数据后用方法3
方法3:
declare Roy_Cursor cursor local for
select count(1)-1,Num,Name from #T group by Num,Name having count(1)>1
declare @con int,@Num int,@Name nvarchar(1)
open Roy_Cursor
fetch next from Roy_Cursor into @con,@Num,@Name
while @@Fetch_status=0
begin
set rowcount @con;
delete #T where Num=@Num and Name=@Name
set rowcount 0;
fetch next from Roy_Cursor into @con,@Num,@Name
end
close Roy_Cursor
deallocate Roy_Cursor--查看结果
select * from #T
/*
Num Name
----------- ----
1 A
2 B(2 行受影响)
*/
insert into a values('001','2008-2-1',90);
insert into a values('003','2008-2-3',10 );
insert into a values('007','2008-2-1',90 );
insert into a values('001','2008-2-5',80 );
insert into a values('003','2008-2-9',60 );
insert into a values('005','2008-2-3',80 );
insert into a values('001','2008-3-3',30 );
insert into a values('007','2008-4-3',50 );
insert into a values('003','2008-10-3',70 );select * from a b where not exists(select * from a where sj>b.sj and hth=b.hth and month(sj)=month(getdate())) and month(sj)=month(getdate())hth sj money
----- ------------------------------------------------------ -----------
007 2008-02-01 00:00:00.000 90
001 2008-02-05 00:00:00.000 80
003 2008-02-09 00:00:00.000 60
005 2008-02-03 00:00:00.000 80(所影响的行数为 4 行)select sum([money]) as total from a b where not exists(select * from a where sj>b.sj and hth=b.hth and month(sj)=month(getdate())) and month(sj)=month(getdate())total
-----------
310(所影响的行数为 1 行)--drop table a
IF OBJECT_ID('tablea') IS NOT NULL
DROP TABLE tablea
Go
CREATE TABLE tablea(hth NVARCHAR(3),sj SMALLDATETIME,money INT)
Go
INSERT INTO tablea
SELECT '001','2008-2-1',90 UNION ALL
SELECT '003','2008-2-3',10 UNION ALL
SELECT '007','2008-2-1',90 UNION ALL
SELECT '001','2008-2-5',80 UNION ALL
SELECT '003','2008-2-9',60 UNION ALL
SELECT '005','2008-2-3',80
GO
--Start
select *
from tablea a
where not exists(select 1
from tablea
where hth = a.hth and sj > a.sj)order by 1
compute sum(a.money)
--Result:
/*
hth sj money
---- ----------------------- -----------
001 2008-02-05 00:00:00 80
003 2008-02-09 00:00:00 60
005 2008-02-03 00:00:00 80
007 2008-02-01 00:00:00 90sum
-----------
310
(5 行受影响)*/
--End
declare @a table(hth varchar(3),sj datetime,money int)insert into @a
select '001','2008-2-1',90
union all
select '003','2008-2-3',10
union all
select '007','2008-2-1',90
union all
select '001','2008-2-5',80
union all
select '003','2008-2-9',60
union all
select '005','2008-2-3',80 select sum(money) from
(select hth,max(sj) as sj from @a group by hth) _a
join @a _b on _a.hth=_b.hth and _a.sj=_b.sjselect sum(money) from @a _a where not exists (select null from @a where _a.hth=hth and _a.sj<sj)
-- Test Data: tablea
IF OBJECT_ID('tablea') IS NOT NULL
DROP TABLE tablea
Go
CREATE TABLE tablea(hth NVARCHAR(8),sj SMALLDATETIME,money INT)
Go
INSERT INTO tablea
SELECT '王001','2008-10-1',90 UNION ALL
SELECT '王003','2008-10-3',10 UNION ALL
SELECT '王007','2008-10-1',90 UNION ALL
SELECT '王001','2008-10-5',80 UNION ALL
SELECT '王003','2008-10-9',60 UNION ALL
SELECT '王005','2008-10-3',80
GO
--Start
select *
from tablea a
where hth like '王%' and --比如所有姓王的
convert(char(7),sj,120) = convert(char(7),getdate(),120) and --在当前年,当前月中
not exists(select 1
from tablea
where hth = a.hth and sj > a.sj)order by 1
compute sum(a.money)
/*(6 行受影响)
hth sj money
-------- ----------------------- -----------
王001 2008-10-05 00:00:00 80
王003 2008-10-09 00:00:00 60
王005 2008-10-03 00:00:00 80
王007 2008-10-01 00:00:00 90sum
-----------
310(5 行受影响)
*/
from jk a
where hth in (
SELECT hth
FROM contract
WHERE flag = '9' AND gh <> '' AND bank LIKE '%银行%' AND kfs IN
(SELECT kfsdm
FROM kfs
WHERE kfsmc LIKE '%开发商%')
)
and convert(char(7),sj,120) = convert(char(7),getdate(),120) and
not exists(select 1
from jk
where hth = a.hth and sj > a.sj)order by 1compute sum(a.csjg)你的这句话.在我程序里面实际用是这样的.你看看这样有什么错误吗?
SELECT '001','2008-02-01',90 UNION ALL
SELECT '003','2008-02-03',10 UNION ALL
SELECT '007','2008-02-01',90 UNION ALL
SELECT '001','2008-02-05',80 UNION ALL
SELECT '003','2008-02-09',60 UNION ALL
SELECT '005','2008-02-03',80
SELECT*,COUNT(*) FROM #A A
WHERE NOT EXISTS (SELECT 1 FROM #A WHERE S_NO=A.S_NO AND S_DATE>A.S_DATE)
GROUP BY S_NO,S_DATE,AMT
ORDER BY S_NO
SELECT* FROM #A A
WHERE (SELECT COUNT(*) FROM #A WHERE S_NO=A.S_NO AND S_DATE>A.S_DATE)<1
ORDER BY S_NO
SELECT* FROM #A A
WHERE S_DATE IN (SELECT TOP 1 S_DATE FROM #A WHERE S_NO=A.S_NO ORDER BY S_DATE DESC)
ORDER BY S_NO
DROP TABLE #A