Tb_AAAA
   id        counts           shijian
   1           5           2008-07-07 12:25:28
   2           6           2008-07-06 16:25:11
   3           7           2008-07-07 12:25:21 
   4           8           2008-07-05 11:25:26
   5           3           2008-07-05 17:15:21
   6           9           2008-07-03 09:25:25 现在我要的到按天数求和
得到如下类似的样式
    Counts             shijian
      9               2008-07-03 
      11              2008-07-05  
      6               2008-07-06 
      12              2008-07-07 

解决方案 »

  1.   

    select  shijian ,sum(counts)
    from Tb_AAAA 
    group by shijian 
      

  2.   

    select Counts=sum(Counts),shijian=(convert(char(10),shijian,120))
    from Tb_AAAA
    group by (convert(char(10),shijian,120))
      

  3.   

    select  convert(varchar(10),shijian,120) ,sum(counts) 
    from Tb_AAAA 
    group by convert(varchar(10),shijian,120)
      

  4.   

    select  convert(varchar(10),shijian,120) ,sum(counts) 
    from Tb_AAAA 
    group by convert(varchar(10),shijian,120)
    明白了,嘿嘿,共同进步
      

  5.   


    没注意是datetime型,2,3楼都是正解
      

  6.   

    select Counts=sum(Counts),shijian=(convert(char(10),shijian,120)) 
    from Tb_AAAA 
    group by (convert(char(10),shijian,120))