这样的问题,比如有个表叫房屋表
id 房号 门洞号 门牌号
1 1 1 101
2 1 1 102
3 1 2 101
4 1 2 102
5 2 1 101
6 2 1 102
7 2 2 101
8 2 2 102 要查出这样的结果
门洞号 房号 套数
1,2 1 4
1,2 2 4请问怎末写查询语句呢
id 房号 门洞号 门牌号
1 1 1 101
2 1 1 102
3 1 2 101
4 1 2 102
5 2 1 101
6 2 1 102
7 2 2 101
8 2 2 102 要查出这样的结果
门洞号 房号 套数
1,2 1 4
1,2 2 4请问怎末写查询语句呢
原著:邹建
改编:爱新觉罗.毓华 2007-12-16 广东深圳表结构,数据如下:
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc需要得到结果:
id values
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加)1. 旧的解决方法(在sql server 2000中只能用函数解决。)
--1. 创建处理函数
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
goCREATE FUNCTION dbo.f_str(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @r varchar(8000)
SET @r = ''
SELECT @r = @r + ',' + value FROM tb WHERE id=@id
RETURN STUFF(@r, 1, 1, '')
END
GO-- 调用函数
SELECt id, value = dbo.f_str(id) FROM tb GROUP BY iddrop table tb
drop function dbo.f_str/*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(所影响的行数为 2 行)
*/--2、另外一种函数.
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go--创建一个合并的函数
create function f_hb(@id int)
returns varchar(8000)
as
begin
declare @str varchar(8000)
set @str = ''
select @str = @str + ',' + cast(value as varchar) from tb where id = @id
set @str = right(@str , len(@str) - 1)
return(@str)
End
go--调用自定义函数得到结果:
select distinct id ,dbo.f_hb(id) as value from tbdrop table tb
drop function dbo.f_hb/*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(所影响的行数为 2 行)
*/2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。)
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
-- 查询处理
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), '<N value="', ','), '"/>', ''), 1, 1, '')
)N
drop table tb/*
id values
----------- -----------
1 aa,bb
2 aaa,bbb,ccc(2 行受影响)
*/
returns varchar(100)
as
begin
declare @s varchar(100)
select @s = isnull(@s+',','')+ltrim(门洞号)
from ta
where 房号 = @fh
return @s
end
go
select 门洞号 = dbo.f_str(房号),房号,count(1)=套数
from ta
group by 房号
insert into tb values(1 , 1 , 1 , 101 )
insert into tb values(2 , 1 , 1 , 102 )
insert into tb values(3 , 1 , 2 , 101 )
insert into tb values(4 , 1 , 2 , 102 )
insert into tb values(5 , 2 , 1 , 101 )
insert into tb values(6 , 2 , 1 , 102 )
insert into tb values(7 , 2 , 2 , 101 )
insert into tb values(8 , 2 , 2 , 102 )
go--创建一个合并的函数
create function f_hb(@房号 int)
returns varchar(8000)
as
begin
declare @str varchar(8000)
set @str = ''
select @str = @str + ',' + cast(门洞号 as varchar) from (select distinct 房号,门洞号 from tb) t where 房号 = @房号
set @str = right(@str , len(@str) - 1)
return(@str)
End
go--调用自定义函数得到结果:
select n.门洞号, m.* from
(select 房号 , count(*) 套数 from tb group by 房号) m,
(select distinct 房号 ,dbo.f_hb(房号) as 门洞号 from (select distinct 房号,门洞号 from tb) t) n
where m.房号 = n.房号drop table tb
drop function dbo.f_hb/*
门洞号 房号 套数
------ ---- -----
1,2 1 4
1,2 2 4(所影响的行数为 2 行)
*/
set nocount on
create table test(id varchar(20),房号 varchar(20),门洞号 varchar(20),门牌号 varchar(20))
insert into test select '1','1','1','101'
insert into test select '2','1','1','102'
insert into test select '3','1','2','101'
insert into test select '4','1','2','102'
insert into test select '5','2','1','101'
insert into test select '6','2','1','102'
insert into test select '7','2','2','101'
insert into test select '8','2','2','102'
go
create function f_get(@房号 varchar(10))
returns varchar(8000)
as
begin
declare @ret varchar(8000)
set @ret=''
select @ret=@ret+门洞号+',' from (select distinct 房号,门洞号 from test)a where 房号=@房号
set @ret=left(@ret,len(@ret)-1)
return @ret
end
go
--测试
select 房号,dbo.f_get(房号),count(*) from test
group by 房号
--删除测试环境
drop table test
drop function f_get
set nocount off
insert tb select 1, 1 , 1 , 101
union all select 2, 1 , 1, 102
union all select 3 , 1 , 2 , 101
union all select 4 , 1 , 2 , 102
union all select 5 , 2 , 1 , 101
union all select 6 , 2 , 1 , 102
union all select 7 ,2 , 2 , 101
union all select 8 ,2, 2 , 102 select 门洞号=convert(varchar(32), stuff((select distinct ','+rtrim(门洞号) from tb t where 房号=tb.房号 for xml path('')),1,1,''))
,房号, 套数=count(id)
from tb
group by 房号/*
门洞号 房号 套数
-------------------------------- ----------- -----------
1,2 1 4
1,2 2 4(2 row(s) affected)
*/
drop table tb
insert into tb values(1 , 1 , 1 , 101 )
insert into tb values(2 , 1 , 1 , 102 )
insert into tb values(3 , 1 , 2 , 101 )
insert into tb values(4 , 1 , 2 , 102 )
insert into tb values(5 , 2 , 1 , 101 )
insert into tb values(6 , 2 , 1 , 102 )
insert into tb values(7 , 2 , 2 , 101 )
insert into tb values(8 , 2 , 2 , 102 )
go--创建一个合并的函数
create function f_hb(@房号 int)
returns varchar(8000)
as
begin
declare @str varchar(8000)
set @str = ''
select @str = @str + ',' + cast(门洞号 as varchar) from (select distinct 房号,门洞号 from tb) t where 房号 = @房号
set @str = right(@str , len(@str) - 1)
return(@str)
End
go--调用自定义函数得到结果:
select distinct 房号 ,dbo.f_hb(房号) as 门洞号 , count(*) from tb group by 房号drop table tb
drop function dbo.f_hb/*
房号 门洞号 套数
---- ------- -----
1 1,2 4
2 1,2 4(所影响的行数为 2 行)
*/
if object_id('tempdb.dbo.#T') is not null drop table #T
create table #T (id int,房号 int,门洞号 int,门牌号 int)
insert into #T
select 1,1,1,101 union all
select 2,1,1,102 union all
select 3,1,2,101 union all
select 4,1,2,102 union all
select 5,2,1,101 union all
select 6,2,1,102 union all
select 7,2,2,101 union all
select 8,2,2,102select
门洞号=(stuff((select distinct ','+ltrim(门洞号) from #T where 房号=a.房号 for xml path('')),1,1,'')),
房号,
套数=count(1)
from #T a group by 房号/*
门洞号 房号 套数
1,2 1 4
1,2 2 4
*/
create table tb(id int, 房号 int, 门洞号 int, 门牌号 int)
insert into tb values(1 , 1 , 1 , 101 )
insert into tb values(2 , 1 , 1 , 102 )
insert into tb values(3 , 1 , 2 , 101 )
insert into tb values(4 , 1 , 2 , 102 )
insert into tb values(5 , 2 , 1 , 101 )
insert into tb values(6 , 2 , 1 , 102 )
insert into tb values(7 , 2 , 2 , 101 )
insert into tb values(8 , 2 , 2 , 102 )
go--创建一个合并的函数
create function wsp(@房号 int)
returns varchar(8000)
as
begin
declare @sql varchar(8000)
select @sql = isnull(@sql+',','') + ltrim(门洞号) from (select distinct 房号,门洞号 from tb where 房号 = @房号)a
return @sql
End
goselect distinct 门洞号=dbo.wsp(房号),房号,套数=(select count(1) from tb where 房号=a.房号)
from tb a