SELECT t.state, t.stor_name, SUM(s.qty) AS TotalSales
FROM sales s JOIN stores t ON (s.stor_id=t.stor_id)
GROUP BY t.state, t.stor_name
ORDER BY TotalSales DESC, t.state, t.stor_name结果如下:
state stor_name TotalSales
WA Doc-U-Mat: Quality Laundry and Books 130
CA Barnum's 125
CA News & Brews 90
OR Bookbeat 80
CA Fricative Bookshop 60
WA Eric the Read Books 8但我想得到每个state中TotalSales最多的stor_name(将以上state列去重),该如何修改上面的sql?
FROM sales s JOIN stores t ON (s.stor_id=t.stor_id)
GROUP BY t.state, t.stor_name
ORDER BY TotalSales DESC, t.state, t.stor_name结果如下:
state stor_name TotalSales
WA Doc-U-Mat: Quality Laundry and Books 130
CA Barnum's 125
CA News & Brews 90
OR Bookbeat 80
CA Fricative Bookshop 60
WA Eric the Read Books 8但我想得到每个state中TotalSales最多的stor_name(将以上state列去重),该如何修改上面的sql?
--2007-10-23于杭州
/*
数据如下:
name val memo
a 2 a2(a的第二个值)
a 1 a1--a的第一个值
a 3 a3:a的第三个值
b 1 b1--b的第一个值
b 3 b3:b的第三个值
b 2 b2b2b2b2
b 4 b4b4
b 5 b5b5b5b5b5
*/
--创建表并插入数据:
create table tb(name varchar(10),val int,memo varchar(20))
insert into tb values('a', 2, 'a2(a的第二个值)')
insert into tb values('a', 1, 'a1--a的第一个值')
insert into tb values('a', 3, 'a3:a的第三个值')
insert into tb values('b', 1, 'b1--b的第一个值')
insert into tb values('b', 3, 'b3:b的第三个值')
insert into tb values('b', 2, 'b2b2b2b2')
insert into tb values('b', 4, 'b4b4')
insert into tb values('b', 5, 'b5b5b5b5b5')
go--一、按name分组取val最大的值所在行的数据。
--方法1:
select a.* from tb a where val = (select max(val) from tb where name = a.name) order by a.name
--方法2:
select a.* from tb a where not exists(select 1 from tb where name = a.name and val > a.val)
--方法3:
select a.* from tb a,(select name,max(val) val from tb group by name) b where a.name = b.name and a.val = b.val order by a.name
--方法4:
select a.* from tb a inner join (select name , max(val) val from tb group by name) b on a.name = b.name and a.val = b.val order by a.name
--方法5
select a.* from tb a where 1 > (select count(*) from tb where name = a.name and val > a.val ) order by a.name
/*
name val memo
---------- ----------- --------------------
a 3 a3:a的第三个值
b 5 b5b5b5b5b5
*/--二、按name分组取val最小的值所在行的数据。
--方法1:
select a.* from tb a where val = (select min(val) from tb where name = a.name) order by a.name
--方法2:
select a.* from tb a where not exists(select 1 from tb where name = a.name and val < a.val)
--方法3:
select a.* from tb a,(select name,min(val) val from tb group by name) b where a.name = b.name and a.val = b.val order by a.name
--方法4:
select a.* from tb a inner join (select name , min(val) val from tb group by name) b on a.name = b.name and a.val = b.val order by a.name
--方法5
select a.* from tb a where 1 > (select count(*) from tb where name = a.name and val < a.val) order by a.name
/*
name val memo
---------- ----------- --------------------
a 1 a1--a的第一个值
b 1 b1--b的第一个值
*/--三、按name分组取第一次出现的行所在的数据。
select a.* from tb a where val = (select top 1 val from tb where name = a.name) order by a.name
/*
name val memo
---------- ----------- --------------------
a 2 a2(a的第二个值)
b 1 b1--b的第一个值
*/--四、按name分组随机取一条数据。
select a.* from tb a where val = (select top 1 val from tb where name = a.name order by newid()) order by a.name
/*
name val memo
---------- ----------- --------------------
a 1 a1--a的第一个值
b 5 b5b5b5b5b5
*/--五、按name分组取最小的两个(N个)val
select a.* from tb a where 2 > (select count(*) from tb where name = a.name and val < a.val ) order by a.name,a.val
select a.* from tb a where val in (select top 2 val from tb where name=a.name order by val) order by a.name,a.val
select a.* from tb a where exists (select count(*) from tb where name = a.name and val < a.val having Count(*) < 2) order by a.name
/*
name val memo
---------- ----------- --------------------
a 1 a1--a的第一个值
a 2 a2(a的第二个值)
b 1 b1--b的第一个值
b 2 b2b2b2b2
*/--六、按name分组取最大的两个(N个)val
select a.* from tb a where 2 > (select count(*) from tb where name = a.name and val > a.val ) order by a.name,a.val
select a.* from tb a where val in (select top 2 val from tb where name=a.name order by val desc) order by a.name,a.val
select a.* from tb a where exists (select count(*) from tb where name = a.name and val > a.val having Count(*) < 2) order by a.name
/*
name val memo
---------- ----------- --------------------
a 2 a2(a的第二个值)
a 3 a3:a的第三个值
b 4 b4b4
b 5 b5b5b5b5b5
*/
(
SELECT t.state, t.stor_name, SUM(s.qty) AS TotalSales, row_number() over(partition by state order by SUM(s.qty) desc) as rowNum
FROM sales s JOIN stores t ON (s.stor_id=t.stor_id)
GROUP BY t.state, t.stor_name
)select state, stor_name, TotalSales
from cte
where rowNum = 1
order by TotalSales desc
在关键字 'with' 附近有语法错误。
服务器: 消息 195,级别 15,状态 1,行 3
'row_number' 不是可以识别的 函数名。
FROM (SELECT t.state, t.stor_id, SUM(s.qty) AS TotalSales
FROM sales s JOIN stores t ON (s.stor_id=t.stor_id)
GROUP BY t.state, t.stor_id) s JOIN
(SELECT t.state, t.stor_id, SUM(s.qty) AS TotalSales
FROM sales s JOIN stores t ON (s.stor_id=t.stor_id)
GROUP BY t.state, t.stor_id) t ON (s.state=t.state)
JOIN stores st ON (s.stor_id=st.stor_id)
WHERE s.totalsales <= t.totalsales
GROUP BY s.state,st.stor_name,s.totalsales
HAVING COUNT(*) <=1
ORDER BY s.state, rank看懂的请帮忙解释一下
FROM (SELECT t.state, t.stor_id, SUM(s.qty) AS TotalSales
FROM sales s JOIN stores t ON (s.stor_id=t.stor_id)
GROUP BY t.state, t.stor_id) s JOIN (SELECT t.state, t.stor_id, SUM(s.qty) AS TotalSales
FROM sales s JOIN stores t ON (s.stor_id=t.stor_id)
GROUP BY t.state, t.stor_id) t ON (s.state=t.state)
JOIN stores st ON (s.stor_id=st.stor_id) WHERE s.totalsales <= t.totalsales
GROUP BY s.state,st.stor_name,s.totalsales
HAVING COUNT(*) <=1
ORDER BY s.state, rank 这样分开好看多了:)