select shopprodItemName,shopprodItemID from [QBS_shopProdItem] where shopID=1022select shopName from [QBS_Shop] where shopID=1022

解决方案 »

  1.   

    這樣?select shopprodItemName,shopprodItemID from [QBS_shopProdItem] where shopID=1022
    Union All
    select shopName, Null from [QBS_Shop] where shopID=1022
      

  2.   

    select a.shopprodItemName,a.shopprodItemID,b.shopName from [QBS_shopProdItem] a, [QBS_Shop] b where a.shopID=1022 and a.a.shopID=b.a.shopID
      

  3.   

    select shopprodItemName,shopprodItemID from [QBS_shopProdItem] where shopID=1022
    union all
    select shopName shopprodItemName , shopprodItemID = 0 from [QBS_Shop] where shopID=1022
      

  4.   

    select shopprodItemName,shopprodItemID from [QBS_shopProdItem] where shopID=1022
    Union All
    select shopName, Null from [QBS_Shop] where shopID=1022--或者是select A.shopprodItemName, A.shopprodItemID, B.shopName from [QBS_shopProdItem] A Inner Join [QBS_Shop] B
    On A.shopID = B.shopID
    where A.shopID=1022
      

  5.   

    偶也来试试。SELECT shpprodItemName, shopproItemID FROM [QBS_shopProItem] aINNER JOIN [QBS_Shop] b ON a.shopID = b.shopID
      

  6.   

    应该是这样的吧:
     Limpire(昨夜小楼) ( ) 信誉:100  2007-08-08 16:11:30  得分: 0  
    select a.shopprodItemName,a.shopprodItemID,b.shopName from [QBS_shopProdItem] a, [QBS_Shop] b where a.shopID=1022 and a.a.shopID=b.a.shopID
      

  7.   

    select a.shopprodItemName,a.shopprodItemID,b. shopName 
    from QBS_shopProdItem a
    left join QBS_Shop b on a. shopID = b. shopID
    where b. shopID=’1022’